NUmbers

Suppose there is a number A.
Let its divisors are : A(itself) , 1, x, y, z,.....
Let B be a number such that B = 1 + x + y + z +.... (Not adding A)
Let the divisors of B are : B, 1, p, q, r,....
and A = 1 + p + q + r + s + ..... (Not adding B)

Find a minimum Number pair ( A, B) satisfying above condition.

Is it (1,1)

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Neelima

Actually i forgot to mention that you dont have to consider the number itself as its divisor in this case.
So case (1,1) is not correct.

Is it (6,6) ?

all perfect numbers satisfy this condition....

6 is the samllest perfect number.