There are some apples if it arranged 3,5,7,9 rows get 1 remember but if it is arranged 11 no remainder .how many apples there?
NOTE : [I][This question was asked by B.VETRI][/I]
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There are some apples if it arranged 3,5,7,9 rows get 1 remember but if it is arranged 11 no remainder .how many apples there?
NOTE : [I][This question was asked by B.VETRI][/I]
hi
i think the ans os 946 apples!:) (plz correct ur spelling.U have written 'remember' instead of 'remainder')
since LCM of 3,5,7,9 comes out to be 945
945+1=946 (1 added since remainder was 1)
also verify by dividng 946 by 11.V get remainder =0;;)
hop my ans correct!
bye:)
Yeah Shenoy u r correct 946 is the answer...
But small correction the LCM(Least Common Factor) for 3,5,7,9 is 315.
From this solution we can know that the number that are divisible by 315 is also divisible by 3,5,7,9.
Try adding 1 to 315 and divide it by 11 its not divisible.
Multiply 315 by 2 and add 1 then divide it by 11 again its not divisible.
Multiplying 315 by 3 gives 945 and add 1 then divide it by 11, now its divisible.
Answer is [B]946[/B]
hi
infact i multiplied each term.i.e 3*5*7*9 =945
945+1=946 (remainder 1 is added to the product result).
sorry for writing LCM in my prev post
bye:)
The answer is 946..
the LCM for 3,5,7,9 is 315.And its 3rd multiple gives the required number 945 which wen added with one yoields 946 that is exactly divisible by 11...