In the addition problem DCB + ACB + BCA, You substitute the four letters with the four digits 2, 7, 5 and 3, in any order. Different letters stand for different digits.
What is the largest value of the sum DCB + ACB + BCA?
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In the addition problem DCB + ACB + BCA, You substitute the four letters with the four digits 2, 7, 5 and 3, in any order. Different letters stand for different digits.
What is the largest value of the sum DCB + ACB + BCA?
I got the value...1579.
A=3, B=7, C=2, D=5. (or) A=5, B=7, C=2, D=3
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suresh
James, what about this one ?
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suresh