remainder

What is the remainder when 2003^1998 is divided by 5

The remainder is 4.

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suresh.

Excellent dude. I admire your skill...Please leave ur solution here.

Any number with the last digit have three then resulting exponent will come in similar order of the following....

3, 9, 7, 1

For Example...
if the number is 13 then the exponent result is...13, 169, 2197, 28561, 371293, 4826809, 62748517,.......

See in the above result the last digit comes 3,9,7,1,3,9,7,....

So In given question exponent digit is 1998.

Divide the 1998/4 (because four digits are similarly coming)

1998/4=499.2

Here the fractional part have 2.....So the last digit is 9.

When u divide 9 by 5 u got the remainder 4.