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A simple Puzzle
A man wanted to go heaven , after few days he died . He entered the entrance
there he had three doors .
if he enters first door he must be in hell for one day then he back to entrance.
in the second door he has to be in hell for two day again he back .
third door is the way to heaven . initilaly he doesn't know anything .
when he get back the doors are getting shuffled . how many days he spent
to enter the heaven .
find it .......
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Re: A simple Puzzle
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second day itself...y bcoz if he enters the first day he'll spent 1 day and come out of that..and then the remaining 2 doors get shuffled(y b'coz he knows very well from which door he came out) and he will enters the 2nd one(which is in real the thrid one..the heaven)...
is that correct
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how many times the door shuffles in a day?
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maximum is the third day............
coz on all the three days he enters the same door.
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ya in the second day itself becoz the door shuffles he enters the third door thinking as the second door
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hi
As per my view he never made it
thanks
Deepasree
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Re: A simple Puzzle
[QUOTE=chanduU;28156]second day itself...y bcoz if he enters the first day he'll spent 1 day and come out of that..and then the remaining 2 doors get shuffled(y b'coz he knows very well from which door he came out) and he will enters the 2nd one(which is in real the thrid one..the heaven)...
is that correct[/QUOTE]
I think dost... you are not correct.
I have presumed few things in the first place. One of them is that he enters one door and that door remains in its place till he comes out. I mean that that door cannot get shuffled. He cannot enter into 1st door and come out from 2nd door.
Secondly I have presumed that the doors get shuffled only after he has entered into any. So the doors get shuffled only once. It is not mentioned that the doors get shuffled each day.
So suppose he entered 1st door. He finds it hell. He will be living there for say 1 day. Then next day he will come out the same door and now he knows that the doors have been shuffled yesterday after he has entered into the door.
He can enter into 2nd or 3rd. He now knows that yesterday's 2nd door is today's 3rd door and vice versa. Let us say he enters 2nd door which was earlier 3rd door. There if he finds hell again and living there for 2 days.
Now when he will come out 2 days later he knows that the doors have been shuffled 2 days ago when he entered. So what was 1st door is now 3rd door and vice versa. So he can safely enters 1st door and get into Heaven.
Please let me know if there is any error in my thinking.
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I think the question is not clear
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I will go bu Chandu and noy by Vasu,because Vasu has contradicted himself.
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I think max ..two days ...
cos..
enter on 1st door,on that day next two doors just shuffled ..when he come out two doors just again shuffled ....
then he entered on 3rd door..and got that one ...
one confusion here that door just shuffled per day but when ...when he come out may be at that time door just shuffled ......
I m correct or not please reply
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hmmm..i think the question is not clear
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the question should have been a bit more clear.....:(
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I Think its maximum of 3 days..Consider tis situation. he enters the first door on the first day finds it is hell and spends a day..NExt day he comes out of it and finds the door has been shuffled..So what was the first door yesterday would be the second or third door today....He again chooses to enter the same door again..If it is shuffled to be the second door he will spend 2 days in hell and come out..Now again he enters the same door and it wil lead to heaven.So maximum of 3 days..however the assumption is the shuffling is proper and its not repeated until a full cycle is completed..
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only one day bec
after oneday he will came back from hell by first door........
bec the heaven door will come to second position when he will come back..................
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min days are 2
please post the ans
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I think the mini days is 0
and max is infinite
coz if the doors are shuffling everyday then he may enter the 1st door and come out and enter the 2nd doors and after coming out of that he may again enter the 1st door and the cycle gets repeated....
let us know the ans
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I want your answer with explaination .According to me its 2 days.
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[QUOTE=govindaraj123;28105]A man wanted to go heaven , after few days he died . He entered the entrance there he had three doors .
if he enters first door he must be in hell for one day then he back to entrance.
in the second door he has to be in hell for two day again he back .
[B]third door is the way to heaven [/B]. initilaly he doesn't know anything .
When he get back the doors are getting shuffled . how many days he spent
to enter the heaven .
find it .......[/QUOTE]
[B]third door is the way to heaven [/B]. Then why he will not enter into 3rd door? direct entry to heaven :)
Anyway answer is Never. He will always be in Hell ;)
Explation:
Let assume door series:
1,2, 3 man will enter door 1 , When he will come out, door series will be
3,1,2 man will enter in 1, (door 1 is now door at 2nd position)
2,3,1 man will again enter in 1 (door 1 is now door at 3rd position)
again same series will happen
1,2,3 and man will enter in 1...(door 1 is now again door at 1st position)
Thanks.
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He will never as If he selects Door 1 or Door 2 or Door 3 ,
but all are being shuffled.
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there is no heaven or hell. It's a lie!
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One day.
Here is how it comes
First day in hell , coming out 2 nd day will make one of two sufflings either 2nd (hell again) shuffled with 3rd (heaven), resulting him to enter in heaven
OR
First gate shuffled with Second gate again leading him to 3rd gate
This is what seems to me.
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through out his life time?? ha ha ha
An interesting question to be fair with you. But some one has to answer this qn :(
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Re: A simple Puzzle
The answer could be none. He enters into heaven on the first day itself.
The question says "if" he enters the door(s). He could just open the door to see whether it he heaven or hell.
That could be the answer, unless the question is to be rephrased.