At a Party, all the members shook hands with other members. There were 91 hankshakes. So howmany members are there ?
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suresh
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At a Party, all the members shook hands with other members. There were 91 hankshakes. So howmany members are there ?
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suresh
[QUOTE=psuresh1982;4821]At a Party, all the members shook hands with other members. There were 91 hankshakes. So howmany members are there ?
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suresh[/QUOTE]
i guess the answer is 182...
The answer is [SIZE="3"][B]14[/B][/SIZE] :D
Yes sutnarcha..You are absolutely correct...can you post your solution ?
It will help to other...
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suresh
I used the following formulae:D
[SIZE="3"]ε (x-1,x-2,x-3…….2)=91[/SIZE] :cool:
here,
[SIZE="2"]ε [/SIZE]is sum of (sigma).
x is number of members, unknown.
The series is only till 2 because we need at least 2 members to shake hands.
91 is given.
Its not so easy, took some time for me.:p
i have one more equation....
n(n+1)/2=91.
If you simply this one, you will get the answer 13. You will add one more to this result...13+1 = 14. Because inital handshake coming from two members..
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suresh