A and B have some balls. If A give him 8 of his balls to B then they have equal number of balls. If B give him 8 of his balls to A then A have 2 times as many as B balls.
Initially howmany balls A and B have ?
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suresh
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A and B have some balls. If A give him 8 of his balls to B then they have equal number of balls. If B give him 8 of his balls to A then A have 2 times as many as B balls.
Initially howmany balls A and B have ?
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suresh
No. of balls with A is 56 and with be is 48.
given that x-8 = y+8 and x+8 = 2(y-8)
where x and y are number of balls with A and B respectively.
[QUOTE=jamesravid;8980]No. of balls with A is 56 and with be is 48.
given that x-8 = y+8 and x+8 = 2(y-8)
where x and y are number of balls with A and B respectively.[/QUOTE]
The answer is not 56 & 48.
The answer is 56 & 40.
now 56-8=48=40+8=48
and
56+8=64=2*(40-8)=2*32=64.
[QUOTE=jainbrijesh;11707]The answer is not 56 & 48.
The answer is 56 & 40.
now 56-8=48=40+8=48
and
56+8=64=2*(40-8)=2*32=64.[/QUOTE]
Gud catch brijesh :-)
Yes its 56 an 40 !!!!