hi friends
a^2+b^2+c^2 = d^2 + e^2.
a,b,c,d,e are 5 consecutive positive integers!:confused:
bye:D
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hi friends
a^2+b^2+c^2 = d^2 + e^2.
a,b,c,d,e are 5 consecutive positive integers!:confused:
bye:D
10^2 + 11^2 + 12 ^ 2 = 13^2 + 14 ^ 2
Cheers!
Kalayama
hi kalayam
right, but one more answer is there!
anyone with other answer?
Please note : a,b,c,d, e are 5 consecutive numbers, but its not necessary that b always comes after a. 'b' can come after 'c' too,etcetc.
eg= 10^2+12^2+13^2= 11^2+14^2.
find such numbers!
bye
:D
(-2)^2+(-1)^2+(0)^2= 1^2+2^2
Cheers!
Kalayama
they should be positive integers kalayama!
Oops! Sorry I overlooked that fact in the question! Million pardons! My mistake. Will work on getting the other combination.
-Shiv
Hi
2^2 + 4^2 + 5^2 = 3^2 + 6^2
45 = 45
Thanks
Manoj:)
good work manoj and kalayama!:D
bye
10^2 + 11^2 + 12^2 = 13^2 + 14^2
[QUOTE=smart_coder;6792]10^2 + 11^2 + 12^2 = 13^2 + 14^2[/QUOTE]
this is already discussed smart coder
Actually what happnd..i joined today only...nd i didnt scroll down to c others answers( i didnt knew that other answers are also written below question) so i answered ur post.
Sorry!!