Hard Mathematical puzzle[3]
If [COLOR="Orange"][B]134261[/B][/COLOR] is [COLOR="Lime"][B]HI[/B][/COLOR] and [COLOR="Orange"][B]103401001738[/B][/COLOR] is [COLOR="Lime"][B]DEAR[/B][/COLOR] and [COLOR="Orange"][B]134261103401001738[/B][/COLOR] is [COLOR="Lime"][B]HI DEAR[/B][/COLOR] then what is [COLOR="Orange"][B]106113212174009905875005909886117221779[/B][/COLOR]?
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suresh
Re: Hard Mathematical puzzle[3]
Hi suresh,
I tried in a different way and got the answer...
Solution:
divide in to three digits
134261 it is 134 and 261, then find the sum of the above digits
134 is 8 : 8th alphabet is H
261 is 9 : 9th alphabet is I
so it HI
similarly for DEAR
103 D
401 E
001 A
738 R
So the answer is "GEEK INTERVIEW"
106 G
113 E
212 E
174 K
009 I
905 N
875 T
005 E
909 R
886 V
117 I
221 E
779 W
:)
Regards,
Elango.
Re: Hard Mathematical puzzle[3]
Nice Work...Keep it up...
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suresh
Re: Hard Mathematical puzzle[3]
i too got each denotes number it appears in alphabet
but same albhabet is denoted by two different set of numbers can u tell
on what basis u assigned numbers
106 g
113 e
212 e
174 k
009 i
905 n
875 t
005 e
909 r
886 v
117 i
221 e
779 w
Re: Hard Mathematical puzzle[3]
There is no unique way to assign the three digit number to each letter. Here the only thing is the total of the three digit number.
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suresh