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Thread: Geniuses

  1. #1
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    Geniuses

    2 geniuses, A and B were given a problem.They were told that integers x and y have been chosen such that 1 < x < y and x+y < 100. A is given the value x+y and B is given the value xy. They then have the following conversation.

    B: I cannot determine the two numbers.
    A: I knew that.
    B: Now I can determine them.
    A: So can I.

    what are the two numbers?


  2. #2
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    Re: Geniuses

    hi smart coder,

    i can't understand the problem...
    For exmaple, if i choose the number x=7 y=9. if i give the value of x+y=16 then why B can't find ? At any value you give i found the x and y.

    i am not clear..that's why i ask you...plz elobarate this one...

    -------------
    suresh

    Last edited by psuresh1982; 01-29-2007 at 01:01 AM.

  3. #3
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    Re: Geniuses

    A is been given the sum and B is given the product.
    They are not allowed to disclose these.
    Like if sum = 16
    then x and y can have many possibilites!!


  4. #4
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    Re: Geniuses

    hi smart coder,

    so your solution have only one combination to satisfy the conditions..

    1<x<y<100 and x+y < 100....

    interesting...i can't find the answer....waiting for someone reply....

    ----------------------
    suresh


  5. #5
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    Re: Geniuses

    Hey Smart Coder i'm getting as 3,2

    X=3
    Y=2

    X+Y = 5
    X*Y = 6

    Which satisfies all the condition. But the doubt here X+Y is more than enough to predict the answer.

    The only thing i found out is X*Y cannot be prime and also its square...

    Thanks
    Manoj


  6. #6
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    Re: Geniuses

    Answer is wrong Manoj


  7. #7
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    Re: Geniuses

    Tell me which part is wrong in my answer, so that i can correct it...

    Thanks
    Manoj


  8. #8
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    Re: Geniuses

    u hvent told ne part of ur solution...u hvent told how u used the statements of the geniuses!!
    explain ur solution in detail and tell wt u deduce after every statement!!


  9. #9
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    Re: Geniuses

    hi smart coder,

    any clue for finding the answer ?

    ---------------
    suresh


  10. #10
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    Re: Geniuses

    xy cannot be a prime or any power of prime!!


  11. #11
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    Re: Geniuses

    hi smart coder,

    "B: I cannot determine the two numbers.".
    What it means the above statement ? B already know the value of xy and x+y. but he doesn't know the value of x and y. Is it correct ?

    Or

    he know only the value of x+y. i am confusing here..that's why i ask give some clue...but whatever you told already manoj mentioned that one..

    sum of x+y is more than 7 then there should be two more combination will come. For example if the sum is 8 then (x=2,y=6) and (x=3,y=5). But you told only one combination will comes here...

    -------------------
    suresh


  12. #12
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    Re: Geniuses

    A is only given the value of x+y and B is only given the value of xy.
    Look the problem is too too tough, it took me a time to understand the whole solution. There is a lot of calculation involved in this question. If u people agree then I wud give the solution!!


  13. #13
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    Re: Geniuses

    yes smart
    , seems to be interesting one, believe me i have thought of many things, but alas not near to solution yet! surely i will like you to leave your solution here!


    bye

    :)
    NEVER SAY DIE.

  14. #14
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    Re: Geniuses

    Here is the answer,

    X=4 and Y =13

    x +y =17 and xy=52

    Is that right Smark Coder?


  15. #15
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    Re: Geniuses

    Solution is available here...
    http://www.qbyte.org/puzzles/p003s.html


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