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My flight takes of at 2am from a place at 18n 10e and landed 10 hrs later at a place with coordinates 36n70w. What is the local time when my plane landed?6:00 am b) 6:40am c) 7:40 d) 7:00...

Asked By: Interview Candidate | Asked On: Jan 4th, 2007

Answered by: BMat on: Mar 19th, 2007

hey SWATI, u messed up an imp thing!1 hour = 60min.(and not 100min.!!)so, 0.33 hr = 20 min (not 33 min)and 0.67 hr = 40 min(not 66 min)And Mr Bera's calculation is based on a simple caln:360 deg o...

Answered by: swati shukla on: Mar 14th, 2007

THERE IS A DISTANCE OF 80 LATTITUDES BETWEEN START N END PORTS.HENCE A TIME GAP OF 80*4=320 MIN.=320/60 hrs=5.333 hrs.after 10 hrs the start port's time is 2am+10hrs=12pmthus end port's local ...

Tcs quantitative aptitude questions

Asked By: nairita | Asked On: Apr 24th, 2006

1. My flight takes of at 2am from a place at 18n 10e and landed 10 hrs later at a place with coordinates 36n70w. What is the local time when my plane landed.A) 6:00 am b) 6:40am c)7:40 d)7:00 e)8:00 2.In 80 coins one coin is counterfiet what is minimum number of weighings to find out counterfiet coin...

Answered by: Murugesan_s on: Jan 27th, 2010

If it is east to west we should add the degrees and convert that to min. then should subtract with the total hrs given. If it is west to east do it inverse manner.

In this problem 70+10=80;80*4 min=320 min=5 hr 20 min
then total hrs given=10 hrs=>10 hr-5 hr 20 min=6 hr 40 min

Answered by: avin2v2 on: Jul 23rd, 2008

3 since in 2 coins only 1 weighing is required 3 also 1 if 2 coins r identical then third coin is defective or else one of the 2 is defective 4,5,6,7,8 needs 1 test 9 requires 2 tests 27 requires...

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