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Asked By: Dinu
| Asked On: Mar 2nd, 2006
Preparation suggestions for aptitude objective arithmetic and quantitative aptitude by r.S. Agarwalbe through with these topicsages ratio and proportiontime and distance percentages time and workrace and games1. 8 men and 10 women can do a work in 25 days, the same work can be done by 10 children and...
Asked By: Interview Candidate
| Asked On: Sep 5th, 2005
49a
Answered by: pktamilselvi on: Jan 10th, 2011
A's age=9, B's age=38
Answered by: mdeulkar on: Dec 20th, 2009
Let present ages be 'a' and 'b'.
after 10 yrs A's age will be a+10
and that of B will be b+10
age of B before 10 yrs = b-10
so given condition is
a+10=2(b-10)
second condition is
a-b=9
solving these two equations we get
b=39
so after 10 yrs B's age will be 39+10=49
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Answered by: jitusonawane
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Member Since Feb-2006 | Answered On : Mar 27th, 2006
11. After 10 years A will be twice the age of B before 10 years and now if the difference is 9 years between them then what is the age of B after 10 years.
Let present ages of A and B be x and y respectively.
According to the question
x+10 = 2(y-10) after solving we get
x-2y = -30 eq. (1)
x-y = 9 eq. (2) after solving above equation we will get there present ages as such A = 48 and B = 39.
After 10 years B will be 49 yrs
Let us take pure milk contains 100 litre
20% replaced by water =>100*20/100=20
100-20=80
now 80 litre milk is available
Again 20% replaced by water =>80*20/100=16
80-16=64
now 64 litre milk is available
Again 20% replaced by water =>64*20/100=12.8
64-12.8=51.2
now 51.2 litre milk is available
10 >ans data is insufficient if L is length of race answer is 25 - (150/L) and it is explained below let L be the length of race and T be the time taken by A to complete race then As...