Write a C program using arrays to count the numbers of positive and negative numbers which accepts the inputs as "size of the array" & "elements of the array" and outputs as "number of negative numbers in an array are" & "numbers of positive numbers in an array are" ?

shweta gupta

 Profile Answers by shweta gupta Questions by shweta gupta

• Jun 25th, 2014

Code
#include<iostream>
#include<stdio.h>
using namespace std;
int main(){
cout<<"enter the size of array"<<endl;
int size,count_neg=0,count_pos=0;
cin>>size;
int a[size];
for(int i=0;i<size;i++){
cout<<"enter element of a["<<i<<"]=";
cin>>a[i];
if((a[i]>>31)==-1) count_neg++;
else count_pos++;
}
cout<<"total negative numbers "<<count_neg<<" and positive number is "<<count_pos;
 
return 0;
}

asdasda

• Aug 11th, 2013

Code
#include<conio.h>
#include<iostream>
 
using namespace std;
 
int value(int a);
 
int main ()
{
    int a, num, count=0;
    
     cout<<"How many values: ";
     cin>>num;
    
    getch ();
    
    
    
int value(int a);
    
    
    for (a=1;a<=num;a++)
    {
    
        cout<<"Enter value "<<a<<": ";
        cout<<endl;
        }
        
        
        getch ();
        return 0;
        }
        
 

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