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Junior Member
Re: pirates of the caribbean
My solution is:
Pirate 5 (Me): 25
Pirate 4 : 25
Pirate 3 : 25
Pirate 2 : 13
Pirate 1 : 12
Here Pirate 4 and 3 will vote for me. I have my own vote at my side. This will keep me in majority. Pirate 4 and 3 will think that if they do not accept my solution then they will murder me but 100 coins will be then distributed among them. Probably they will get 25 only which anyway they are getting. So why not accept my solution?
Pirate 1 and 2 will not accept. But they what will happen? Nothing. They constitute lesser than 50 % in the total quorum. So anyway I will get more than others and I will remain alive.
Correct me if I am wrong.
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Junior Member
Re: pirates of the caribbean
pirate 5 = 22
pirate 4 = 21
pirate 3 = 20
pirate 2 = 19
pirate 1 = 18
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