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Junior Member
Re: Count the Digits
hii guys here is a doubt for me you are giving answers but can we remember as such
142857 so give us method to find the number tooo...............
heres my method for this
first we must get 9 in the last digit after six additions of same number meaning the last digit of the number multiplied by 7 must give 9 in the last position of resultant so it means only 7 is possible as last digit in the number....so we place 7 in last digit position...
number:_________7
now,we get carry 4 (7*7=49) to next digit so we need only 5 in next digit.......
to get 5 only 5 is possible(since 7*5=35)
number:_______57
now,we get carry 3(7*5=35) to next digit so we need only 6 in next digit...
to get 6 only 8 is possible(since 7*8=56)
number:______857
next,similarly carry:5 rdigit:4 nextdigit:2(7*2=14)
number:____2857
next,carry:1 rdigit:8 nextdigit:4(7*4=28)
number:__42857
next carry:2 rdigit:7 nextdigit:1(7*1=7)
number:142857
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