An array of 100 elements consists of only 0's and 1's

An array of 100 elements consists of only 0's and 1's. One should count the number of 1's or 0's with a very few lines of C program. One method is to sum all the elements to get the number of 1's. But there should be a built-in command to get the answer in a single line of program, I suppose. Please notify me if anyone knows the answer.

[B]Question asked by visitor Vanitha[/b]

in C you can do it in one line

for(i = 0; i < ARR_SIZ ; i++) (num[i] == 1) ? ones++: zeros++;

a sample program could be...
------------------

#include <stdio.h>
#define ARR_SIZ 100

int main()
{

int num[ARR_SIZ],
i,
ones,
zeros;

ones = 0;
zeros = 0;

/* array fill */
for (i = 0; i < ARR_SIZ; i++)
num[i] = (i % 2) == 0 ? 1: 0;

/* array processing */
for(i = 0; i < ARR_SIZ ; i++)
(num[i] == 1) ? ones++: zeros++;

printf("\nones: %d\tzeros: %d\n",
ones,
zeros);

return 0;

}
------------

hth