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Anitha walks from her home to Temple and back home. Her brother Amuthan walks from Temple to their home and back to Temple. They both walk at constant speeds ( not necessarily the same). They leave exactly at the same time and meet for the first time 7 Km from Temple. Each one continues on their way to their destination where they both trun around without any loss of time. They meet the second time 4 Km from their home.
What is the distance between Temple and their home?
[QUOTE=jamesravid;2670]Anitha walks from her home to Temple and back home. Her brother Amuthan walks from Temple to their home and back to Temple. They both walk at constant speeds ( not necessarily the same). They leave exactly at the same time and meet for the first time 7 Km from Temple. Each one continues on their way to their destination where they both trun around without any loss of time. They meet the second time 4 Km from their home.
What is the distance between Temple and their home?[/QUOTE]
I think the answer is 17Km...
Am i correct..?
Exactly correct Answer. Very good work man.
I suggest you to post the solution.
Distance is d then the equation to be solved is
d-7/7 = d+3/d-3
which yields d = 17
[QUOTE=hsundar;2795]Distance is d then the equation to be solved is
d-7/7 = d+3/d-3
which yields d = 17[/QUOTE]
Hi,
Can you explain the equation?
[QUOTE=vignan;32186]Hi,
Can you explain the equation?[/QUOTE]
Well... i tried the using a similar equation. that gave me 17.
lets say distance betn temple and home is d.
find the ratio of their distance travelled. for 7 km its... (d-7)/7
next time when they meet, its 4 km... (2d-4)/(d+4)
solve the eqn... (d-7)/7 = (2d-4)/(d+4)
u ll get d=17