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Area of Rectangle

This is a discussion on Area of Rectangle within the Brainteasers forums, part of the Brain Gym category; Rectangle ABCD has sides AB and BC in the ratio 3 : 1. If the diagonal AC is 5, then find the area of the rectangle. -- James....

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#1 (permalink)   09-17-2006

jamesravid Expert Member   Join Date: Jun 2006 Location: India Posts: 411 Thanks: 15 Thanked 33 Times in 25 Posts

Area of Rectangle Rectangle ABCD has sides AB and BC in the ratio 3 : 1. If the diagonal AC is 5, then find the area of the rectangle. -- James.

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#2 (permalink)   09-18-2006

SriramKrishna Junior Member   Join Date: Sep 2006 Posts: 27 Thanks: 0 Thanked 2 Times in 2 Posts

Re: Area of Rectangle From the given data I got the length of the rectangle as 15 and breadth as 5. So area of the rectangle is 75.

#3 (permalink)   09-19-2006

jamesravid Expert Member   Join Date: Jun 2006 Location: India Posts: 411 Thanks: 15 Thanked 33 Times in 25 Posts

Re: Area of Rectangle It is completely wrong Sriram -- James

#4 (permalink)   09-24-2006

SriramKrishna Junior Member   Join Date: Sep 2006 Posts: 27 Thanks: 0 Thanked 2 Times in 2 Posts

Re: Area of Rectangle James could you give the answer and the approach. I could not figure out the way for solving this.

#5 (permalink)   10-09-2006

jamesravid Expert Member   Join Date: Jun 2006 Location: India Posts: 411 Thanks: 15 Thanked 33 Times in 25 Posts

Re: Area of Rectangle Let us say length of AB and BC are 3a,a. Then area of the rectagle is 3a^2. By pythagoras theorem, 9a^2 + a^2 = 5^2 => 10 a^2 = 25 => a^2 = 2.5 therefore area of the rectanga is 7.5 Square units. -- James

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