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Hard Mathematical puzzle[3]

This is a discussion on Hard Mathematical puzzle[3] within the Mathematical Puzzles forums, part of the Brain Gym category; If 134261 is HI and 103401001738 is DEAR and 134261103401001738 is HI DEAR then what is 106113212174009905875005909886117221779 ? ---------------------- suresh...


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  #1 (permalink)  
Old 10-19-2007
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Hard Mathematical puzzle[3]

If 134261 is HI and 103401001738 is DEAR and 134261103401001738 is HI DEAR then what is 106113212174009905875005909886117221779?

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suresh
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Old 10-22-2007
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Re: Hard Mathematical puzzle[3]

Hi suresh,

I tried in a different way and got the answer...

Solution:
divide in to three digits
134261 it is 134 and 261, then find the sum of the above digits
134 is 8 : 8th alphabet is H
261 is 9 : 9th alphabet is I

so it HI

similarly for DEAR
103 D
401 E
001 A
738 R

So the answer is "GEEK INTERVIEW"
106 G
113 E
212 E
174 K
009 I
905 N
875 T
005 E
909 R
886 V
117 I
221 E
779 W




Regards,
Elango.
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Old 10-22-2007
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Re: Hard Mathematical puzzle[3]

Nice Work...Keep it up...

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suresh
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Old 10-22-2007
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Re: Hard Mathematical puzzle[3]

i too got each denotes number it appears in alphabet
but same albhabet is denoted by two different set of numbers can u tell
on what basis u assigned numbers

106 g
113 e
212 e
174 k
009 i
905 n
875 t
005 e
909 r
886 v
117 i
221 e
779 w
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Old 10-22-2007
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Re: Hard Mathematical puzzle[3]

There is no unique way to assign the three digit number to each letter. Here the only thing is the total of the three digit number.

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suresh
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