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Thread: puzzle

  1. #1
    Junior Member
    Join Date
    Jul 2007
    Answers
    21

    puzzle

    1.There r two person each having same amount of
    Marbles in the beginning and 1st person gains 20 more
    From the second person and he eventually lose two
    Thirds of it during the play and now the second person has 4times marbles of what first person is having now.find how much marbles did each had in the
    beginning ?


  2. #2
    Expert Member
    Join Date
    Jun 2006
    Answers
    410

    Re: puzzle

    Each of them started with 100 marbles.

    It is given than 4( (a+20)/3 ) = 5a/3 +40/3 -20

    solving this you will get a = 100


  3. #3
    Junior Member
    Join Date
    Nov 2006
    Answers
    25

    Lightbulb Re: puzzle

    Yes, james is correct. i also got 100.

    Solution:
    1) both having intially x
    2) second loses 20 to first one
    so x+20 = x-20
    3)first loses 2/3(x+20) to second, then second has 4 times of first

    4 * 1/3(x+20) = (x-20)+ 2/3(x+20)

    solving this we get 100.




  4. #4
    Junior Member
    Join Date
    Jul 2007
    Answers
    21

    Re: puzzle

    Quote Originally Posted by TigerElango View Post
    Yes, james is correct. i also got 100.

    Solution:
    1) both having intially x
    2) second loses 20 to first one
    so x+20 = x-20
    3)first loses 2/3(x+20) to second, then second has 4 times of first

    4 * 1/3(x+20) = (x-20)+ 2/3(x+20)

    solving this we get 100.


    good

    continue it .......


  5. #5
    Junior Member
    Join Date
    Jul 2007
    Answers
    1

    Re: puzzle

    it good one..


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