John left home at 8:00AM for the bus station. When he arrived at the bus station, the clock at the bus station showed 8:05AM. He immediately found out that he forgot his math book and returned home. When he got back home, the clock at home showed 8:18AM.

Assume his walking speed is always the same. How many minutes was his clock faster?

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Brijesh Jain

4 minutes faster!!

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[B][COLOR="Blue"]Anyone who thinks he knows all the answers, must not be up-to-date on the questions[/COLOR][/B]
[B]Anshul[/B]:)

Yes, it's the right answer.But whenever you give answer of any brainteaser, please always give explation also.

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Brijesh Jain

I give answer. If someone asks I always give the solution.

Let the John's clock be x minutes faster
To reach from home to station John took 5+x minutes.
To reach from station to home John took 18-5-x = 13-x minutes
Both time should be equal since his speed is always same.
5+x = 13-x
hence x = 4 minutes.

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[B][COLOR="Blue"]Anyone who thinks he knows all the answers, must not be up-to-date on the questions[/COLOR][/B]
[B]Anshul[/B]:)

One more simple solution is, When he got back home, the clock at home showed 8:18AM.John left home at 8:00AM.
total time is 18 min.One side time is 9min.bus station showed 8:05AM.
so, john's watch is 4 min faster, in real he left the home at 7:56AM.

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Brijesh Jain

Yes. good solution

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[B][COLOR="Blue"]Anyone who thinks he knows all the answers, must not be up-to-date on the questions[/COLOR][/B]
[B]Anshul[/B]:)