1. very very simple puzzle

Hi guys,

Five farmers have 7, 9, 11, 13 & 14 apple trees, respectively in their orchards.

Last year, each of them discovered that every tree in their own orchard bore
exactly the same number of apples.

Further, if the third farmer gives one apple tothe first,

& the fifth gives three to each of the second and the fourth

They would all have exactly the same number of apples.

Then guys...............

What were the yields per tree in the orchards of the third and fourth farmers?

Try u r best...

All t best.

Thanks & Regards,

Riju.

2. Re: very very simple puzzle

1) All trees of a single farmer bore equal number of fruits i.e say 1st farmer has 7 trees and each tree bears 'a' number of fruits. Therefore 1st farmer will have 7a apples.

2) Similarly 2,3,4,5 farmers will have 9b,11c,13d,14e apples respectively.

3)Now third farmer gives one apple to the first
Hence 11c-1 = 7a+1
Also the fifth gives three to each of the second and the fourth
Hence 14e-6=9b+3=13d+3

4) Since after doing this all have exactly the same number of apples
we can say 14e-6=7a+1
Thus 14e-7a=7 i.e. 2e-a=1

Now put a=17 Thus e=9
5) Now put the above values in step 3, we get c=11, d=9, b=13
Thus a=17, b=13, c= 11, d= 9, e=9.

These are the apples yielded per tree for each farmer. If you put these values in step 3, you'll see that each farmer will have 120 apples.

Don't forget to confirm the answer, Rijus

3. Re: very very simple puzzle

Dear vcite,

U r absltly right.

The Third & fourth farmer will yeild 11 & 9 apple trees.

Congrats !!!!!!!

Absltly Brilliant ............

Keep it up...

Thanks & Regards,
Riju.

4.

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