A bus started from bustand at 8.00a m and after 30 min staying at destination, it returned

A bus started from bustand at 8.00a m and after 30 min staying at destination, it returned
back to the bustand. the destination is 27 miles from the bustand. the speed of the bus 50 percent fast speed. at what time it returns to the bustand
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chandradeepika

  • Jun 11th, 2008
 

a bus cover 27miles with 18mph in=27/18 =1hr30min and it wait at stand=30min.
after this speed of return increases by 50%. so 50% of 18mph=9mph
total speed of returning=18+9=27
then in return it take 27/27=1hr.
then total time in journey=1+1.30+0.30=3hr
so it will come at 8+3hr=11am.
so ans=11am

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