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A bus started from bustand at 8.00a m and after 30 min staying at destination, it returned
A bus started from bustand at 8.00a m and after 30 min staying at destination, it returned
back to the bustand. the destination is 27 miles from the bustand. the speed of the bus 50 percent fast speed. at what time it returns to the bustand



  
Total Answers and Comments: 2 Last Update: July 01, 2008     Asked by: swatirose88 
  
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June 11, 2008 12:13:02   #1  
chandradeepika Member Since: May 2008   Contribution: 36    

RE: A bus started from bustand at 8.00a m and after 30 min staying at destination, it returned
a bus cover 27miles with 18mph in=27/18 =1hr30min and it wait at stand=30min.
after this speed of return increases by 50%. so 50% of 18mph=9mph
total speed of returning=18+9=27
then in return it take 27/27=1hr.
then total time in journey=1+1.30+0.30=3hr
so it will come at 8+3hr=11am.
so ans=11am

 
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July 01, 2008 13:45:07   #2  
rajani_vaddepalli15 Member Since: June 2008   Contribution: 19    

RE: A bus started from bustand at 8.00a m and after 30 min staying at destination, it returned
how did you considered that the speed is 18kmph?
 
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