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| Total Answers and Comments: 2 |
Last Update: May 21, 2008 Asked by: swatirose88 |
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Submitted by: dinesh_sun7
the answer in 3188 since 8,5 is the 54th location in the array and each bytes occupying 4 bytes it will be in the starting addres 3000+188=3188 ok?
Above answer was rated as good by the following members:
rajani_vaddepalli15 | 4.In two dimensional array X(7,9) each element occupies 2 bytes of memory.If the address of first element X(1,1)is 1258 then what will be the address of the element X(5,8) ? whats the ans
One circular array is given(means memory allocation tales place in circular fashion) diamension(9X7) and sarting add. is 3000,What is the address od (2,3)........ What is the answer? Pls explain to me with steps
In a two-dimensional array, X (9, 7), with each element occupying 4 bytes of memory, with the address of the first element X (1, 1) is 3000, find the address of X (8, 5). Latest Answer : Since the address starts at 3000 and allocating 4 bytes to each location, i guess the address of X(8,5) will be 3212...correct?? ...
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