anon1987

 Profile Answers by anon1987 

• Dec 7th, 2009

 

Let us consider that the distance betwn each ports be 1 mile because all of them are same ..
By the question we find that the speed of the ship frm the port is equal 2 distance from the port 2 the port   I , so he will arrive at I in 1 hr , n similarly the other ship will reach J in 1 hr as port  H is 2 mile aways from port

Therefore the meeting point must be betwn the port I and J , (ANS ) ,

By calculation i m getting the metting point as 0.6 miles from the  port I and 0.4 miles from the port J..

Formula is ::
Distance covered =6H/ (H+I)   for the ship left from the port ..

vikas006gupta

 Profile Answers by vikas006gupta 

• Jan 6th, 2010

 

                    
                           S1                                                       S2 
                                |  ---  |  ---  |---  |  ---  |  ---  |  ---  |
                                
                           port       G       H    I         J        K       L
 

          The speed of ship from port is  'I' let us consider be 3 units
                                               from L is   'H' let consider it be 2 units
Thus when ship S1 is at I, ship S2 is at J. Now distance bet them is 1 unit
So , as their speeds are in ratio 3 : 2, thus it is equivalent to 1/2 : 1/3.thus now s1 is at mid pt bet I and J , and S2 is 1/6 units from mid pt, theirfore they will meet some where bet this region    and that is ofcourse close to J.