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A father has 8 children ,he takes 3 at a time to a zoo. What is the probability of a child going to the zoo.

  
Total Answers and Comments: 12 Last Update: August 29, 2007   
  
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April 19, 2005 11:49:55   #1  
sandeep        

RE: A father has 8 children ,he takes 3 at a time to a zoo. What is the probability of a child going to ...
the probability is 1/8
 
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May 17, 2005 00:40:35   #2  
Ashutosh Joshi        

RE: A father has 8 children ,he takes 3 at a time to a zoo. What is the probability of a child going to ...
3/8
 
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July 05, 2005 01:06:45   #3  
Amit        

RE: A father has 8 children ,he takes 3 at a time to a zoo. What is the probability of a child going to ...
3/8
 
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July 29, 2005 23:11:02   #4  
KIRAN        

RE: A father has 8 children ,he takes 3 at a time to a zoo. What is the probability of a child going to ...
3/8
 
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September 23, 2005 11:55:40   #5  
priya        

RE: A father has 8 children ,he takes 3 at a time to a...

n(s)=8c3=56

n(E)=8c1=8

so probability=n(E)/n(s)=8/56

                                =1/7


 
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February 28, 2006 05:37:07   #6  
rohith        

RE: A father has 8 children ,he takes 3 at a time to a...
3:3:2
 
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March 23, 2006 16:18:08   #7  
mtgeek        

RE: A father has 8 children ,he takes 3 at a time to a...
Probabality has to be 3/8, because his father picks 3 out of 8 to go to the zoo. You have a chance of 3 out of 8 to be in that group.
 
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June 19, 2007 23:36:22   #8  
Vivekanand        

RE: A father has 8 children ,he takes 3 at a time to a...
The question is that one child getting selected by his father. So probability of selecting this guy is 1/8 and there are remaining 2 positions, for which he would pick by 8C2. The total no.of combinations are 8C3. So the probability is

             1/8 * 8C2            1/8 * 8*7/2                
            --------------    =    --------------------   =    1/16 = 0.066
                8C3                     8*7*6/3*2*1

 
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July 16, 2007 08:04:18   #9  
Rachit Agrawal        

RE: A father has 8 children ,he takes 3 at a time to a...
Well Vivekanand made a small mistake. It should be

1. Select the child. And then out of & children there is 7C2 ways to select any two. So number of favorable chances are 7C2 * 1 = 21

2. Total number of cases are 8C3 = 56

so the Probability is 7C2/8C3 = 21/56 = 3/8


 
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July 17, 2007 13:34:17   #10  
anish007 Member Since: July 2007   Contribution: 1    

RE: A father has 8 children ,he takes 3 at a time to a...
probability is ((1/8)*(7C2))/(7C3)=3/40
 
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