What percent of the resulting solution in the jug is salt?

A 5 liter jug contains 4 liters of a salt water solution that is 15 percent salt. If 1.5 liters of the solution spills out of the jug, and the jug is then filled to capacity with water, approximately what percent of the resulting solution in the jug is salt?
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varshaji

  • Feb 19th, 2009
 

Given:
Actual salt water = 4 litres (with 15% salt in it)
Spilled out = 1.5 litres (with 15% salt in it)
Remaining is = 2.5 litres (with 15% salt in it)
Now filled with pure water = 2.5 litres (with 0% salt)

Solution:
So, new quantity = 5 litres
Water quantity doubles and
hence, salt must dilute into half
Therefore, salt % is 7.5%

manish deo

  • Mar 4th, 2009
 

The answer is 7.5%. This is how we get it.

Initially quantity of salt = (15/100)*4=.6 ltr

When 1.5 ltr sol spills, the salt lost is (15/100)*1.5=.225 ltr

Now salt left = .6-.225=.375 ltrs as jug is filled to its capacity,

Total sol = 5ltrs % of salt =(0.375/5)*100=7.5%

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gunnu dsouza

  • Jun 13th, 2010
 

Initial salt water solution=4 ltrs
When 1.5 ltrs is spilled out, remaining salt water solution=2.5 ltrs
Quantity of salt in this solution=2.5*(15/100)=0.375 ltrs
When more water is added, total solution=5 ltrs
Therefore quantity of salt in this solution remains=0.375 ltrs
Thus percentage of salt in this solution=(0.375/5)*100=7.5%

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chaitanyahiremath

  • Aug 4th, 2010
 

Amount of salt present=(4*15)/100=3/5ltr
Salt present after 1.5 ltr lost ie remaining 2.5ltr=(2.5*(3/5))/4=3/8
% of Salt present now finally after filling jug completely ie for 5 ltr=(100*3/8))/5=7.5%

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aman15490

  • Aug 8th, 2010
 

I am really amazed after looking at the number of people who have thanked a post which is not correct.

Answer is not 7.5 as posted by many.What the basic mistake in most of the answer is that when 1.5 litres of solution is removed from Jug then water would also be removed which is ignored by many.

According to question ratio of salt and water is 3:17. thus initially salt would be 4*15/100 and water would be 4*85/100

Now when 1.5 liters of solution is removed then 

salt removed=1.5*3/20 and water removed 1.5*17/20

Thus salt present at last is=75/200 and water present at last is 4*85/100-17*1.5/20 +1.5(as water is added).

Thus ratio of water and salt becomes 725:75.

thus out of 4 liters of solution salt is 75/8 % ==9.375%

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