Sandeep Kumar
Answered On : Jun 17th, 2005
A+10=2(B-10)
&
A-B=9 i.e. A=B+9,
now,
putting it in earlier eqn.
B+19=2B-20
so B=39,
after 10 years B will be 39+10=49.
Ans =49
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TRIVENI
Answered On : Jun 18th, 2005
please send me the solution for this problem
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kavita kanyal
Answered On : Jul 7th, 2005
There will be two anwers as the difference is given. It's not given specifically that
A-B=9 or B-A=9
With A-B=9 :
eqns will be: 2B-A=30
and A-B=9
it will give B=39
hence Ans=39+10=49
With B-A=9 :
eqns will be: 2B-A=30
and B-A=9
hence B=21
hence Ans=21+10=31

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Here
Answered On : Jul 17th, 2005
two answers
1. If A= 12, then B=21
2. If A= 48, then B= 39
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Here
Answered On : Jul 17th, 2005
thus, 10 years later, B will either be 49 or 31
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GAURAV RASTOGI
Answered On : Sep 5th, 2005
let the age of b=x
let the age of a = x-9
then the equation is
(x-9)=x
after 10 years in a and before ten years in b
new equation will be
(x-9+10)=2(x-10)
then
the value of x =21 years
and after 10 years will be 31 years
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RAJESH
Answered On : Dec 17th, 2005
let present age of a & b is 'A','B' respectively.after 10 yrs age of 'a' is A+10;before 10 yrs age of b is B-10.
given that A+10=2*(B-10)
and A-B=9
by solving above two we get B=39;
so after 10 yrs the age of b is 49
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VIKRAM MAJJARI
Answered On : Feb 25th, 2006
answer:49let A's present age=xAfter 10 years A's age=10+xLet B's age before 10 years =y-10(present age=y)a/c to problem,10+x=2(y-10)=>x-2y=-30--------------1st eq.alsox-y=9----------------------2nd eqsolving 1st and 2nd eqwe get x=48 and y=39so B's age after 10 years is y+10 i.e; 39+10=49
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sunitha
Answered On : Apr 7th, 2006
the answer is........
B's age after 10 years will be
31 if B-A=9 is taken
or 49 if A-B is taken
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shravani
Answered On : Apr 8th, 2006
Let the age of A now is X.
age of B=X-9.
Aft 10 yrs As age =x+10.
B4 10 yrs Bs age =x-19.
Given, Xx+10=2X-38
This gives X=48
As age 48 now. Bs age 39 now.
After 10 yrs B's age will be 49.
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anna
Answered On : Jun 26th, 2006
Let present age be A= x yr, B = y yr. Since A is Twice theage of B at some point A is older than Bx-y = 9x+10 = 2 (y-10)y = 39 present age. After 10 yr B's age = 49
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pramod reddy
Answered On : Dec 26th, 2006
We get two values for B.We are given only the difference between A & B,But not who is older.So, the difference can be (A-B) or (B-A).Hence, we get B values as 39 & 21 respectively. NOw, just go back to the question and verify to check the required conditions.
The answer, i.e age of B after 10 years is 49.
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yogeshgurav007
Answered On : Feb 7th, 2007
After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years between them then what is the age of B after 10 yearsConsiderAge of A is ==> xnow if the difference is 9 years between themSo Age of B will be ==> (x-9)After 10 yearsA will be twice the age of B before 10 yearsx + 10 = 2 ( x - 9 )x + 10 = 2x - 1828 = xmeans now Age of A==> x = 28After 10 years i.e. Age of A will be 38, which is 2(x-9) ==> 2 X 19Means now age of B is (x-9)==> 19Ans is Age of B (now) >>> 19 A Bnow 28 19after 1o years 38 29
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Munish Jain
Answered On : Feb 8th, 2007
Dear Trivani
Please check the answer and reply me back about the question
Regards
Ans:
A+10=2(B-10) &
A-B=9 i.e. A=B+9,
now, putting it in earlier eqn.
B+19=2B-20
so B=39,
after 10 years B will be 39+10=49.
Ans =49
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puja
Answered On : Apr 23rd, 2007
let the current age of A and B is x and y.
so according to question
after 10n yrs the age of A becomes twice the age of B before 10 years so---
X+10=2(Y-10)
==> X-2Y=-30 Eqn-1
according to second condition the difference b/w there age is---9 yrs
X-Y=9 Eqn-2
now solving equation 1 and equation 2 the result is.....
age of A is 48 and of B is 39
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soujanya
Answered On : Jun 30th, 2007
A+10=2(B-10)
& A-B=9
so A-2B=-30
A-B=9
-B=-39
so B=39+10
B=49
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c.praveen sagar reddy
Answered On : Aug 26th, 2007
According to given statement A+10=2(B-10) and also given that DIFFERENCE IS 9 then A-B=9 OR B-A=9 then problem is as follows substitute in the above A=B+9 then
B+19=2B-20 then
B=39
OR
If we consider
B-A=9 then
B=A+9 then
B+1=2B-20 then
B=21
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(A+10)=2(B-10)
=> A-2B=-30
and A-B=9
so the answer is 58
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49 years
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sorry gys my 1st answer was wrong it is actually a's age after 10 years
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let A's and B's present age be a,b years respectively.
then a-b=9--->1
a+10=2(b-10) ie. a-2b=-30--->2
1-2=>
b=39;
so the age of B after 10 years will be 49
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B will be of 49 yrs after 10 yrs
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A+10=2(B-10)
=>A-2B=-30
A-B=9
so substituting A-B=9 in A-2B=-30
we get -B=-39
so , after 10 yrs B=39+10=49
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Letpresent ages be'a' and 'b'.
after 10 yrs A's age will be a+10
and that of B will be b+10
age of B before 10 yrs = b-10
so given condition is
a+10=2(b-10)
second condition is
a-b=9
solving these two equations we get
b=39
so after 10 yrs B's age will be 39+10=49
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A's age=9, B's age=38
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