let the age of b=x let the age of a = x-9 then the equation is (x-9)=x after 10 years in a and before ten years in b new equation will be (x-9+10)=2(x-10) then the value of x =21 years and after 10 years will be 31 years
answer:49let A's present age=xAfter 10 years A's age=10+xLet B's age before 10 years =y-10(present age=y)a/c to problem,10+x=2(y-10)=>x-2y=-30--------------1st eq.alsox-y=9----------------------2nd eqsolving 1st and 2nd eqwe get x=48 and y=39so B's age after 10 years is y+10 i.e; 39+10=49
We get two values for B.We are given only the difference between A & B,But not who is older.So, the difference can be (A-B) or (B-A).Hence, we get B values as 39 & 21 respectively. NOw, just go back to the question and verify to check the required conditions.
After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years between them then what is the age of B after 10 yearsConsiderAge of A is ==> xnow if the difference is 9 years between themSo Age of B will be ==> (x-9)After 10 yearsA will be twice the age of B before 10 yearsx + 10 = 2 ( x - 9 )x + 10 = 2x - 1828 = xmeans now Age of A==> x = 28After 10 years i.e. Age of A will be 38, which is 2(x-9) ==> 2 X 19Means now age of B is (x-9)==> 19Ans is Age of B (now) >>> 19 A Bnow 28 19after 1o years 38 29
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