RE: After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet...
let the age of b=x let the age of a = x-9 then the equation is (x-9)=x after 10 years in a and before ten years in b new equation will be (x-9+10)=2(x-10) then the value of x =21 years and after 10 years will be 31 years
RE: After 10 years A will be twice the age of B...
answer:49let A's present age=xAfter 10 years A's age=10+xLet B's age before 10 years =y-10(present age=y)a/c to problem,10+x=2(y-10)=>x-2y=-30--------------1st eq.alsox-y=9----------------------2nd eqsolving 1st and 2nd eqwe get x=48 and y=39so B's age after 10 years is y+10 i.e; 39+10=49