After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years between them then what is the age of B after 10 years

A+10=2(B-10) 
 
& 
 
A-B=9 i.e. A=B+9, 
 
now, 
putting it in earlier eqn. 
 
B+19=2B-20 
 
so B=39, 
 
after 10 years B will be 39+10=49. 
 
Ans =49

please send me the solution for this problem 

There will be two anwers as the difference is given. It's not given specifically that  
A-B=9 or B-A=9 
 
With A-B=9 : 
eqns will be: 2B-A=30 
and A-B=9 
it will give B=39 
hence Ans=39+10=49 
 
With B-A=9 : 
 
eqns will be: 2B-A=30 
and B-A=9 
hence B=21 
hence Ans=21+10=31

two answers 
1. If A= 12, then B=21 
2. If A= 48, then B= 39

thus, 10 years later, B will either be 49 or 31

let the age of b=x 
let the age of a = x-9 
then the equation is  
(x-9)=x 
after 10 years in a and before ten years in b 
new equation will be 
(x-9+10)=2(x-10) 
then  
the value of x =21 years 
and after 10 years will be 31 years 

let present age of a & b is 'A','B' respectively.after 10 yrs age of 'a' is A+10;before 10 yrs age of b is B-10.

given that A+10=2*(B-10)

and A-B=9

by solving above two we get B=39;

so after 10 yrs the age of b is 49  

answer:49let A's present age=xAfter 10 years A's age=10+xLet B's age before 10 years =y-10(present age=y)a/c to problem,10+x=2(y-10)=>x-2y=-30--------------1st eq.alsox-y=9----------------------2nd eqsolving 1st and 2nd eqwe get x=48 and y=39so B's age after 10 years is y+10 i.e; 39+10=49

the answer is........

B's age after 10 years will be

31 if B-A=9 is taken

or 49 if A-B is taken

Let the age of A now is X.

age of B=X-9.

Aft 10 yrs As age =x+10.

B4 10 yrs Bs age =x-19.

Given, Xx+10=2X-38

This gives X=48

 

As age 48 now. Bs age 39 now.

After 10 yrs B's age will be 49.

Let present age be A= x yr, B = y yr. Since A is Twice theage of B at some point A is older than Bx-y = 9x+10 = 2 (y-10)y = 39 present age. After 10 yr B's age = 49

We get two values for B.We are given only the difference between A & B,But not who is older.So, the difference can be (A-B) or (B-A).Hence, we get B values as 39 & 21 respectively. NOw, just go back to the question and verify to check the required conditions.

The answer, i.e age of B after 10 years is 49.

After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years between them then what is the age of B after 10 yearsConsiderAge of A is ==> xnow if the difference is 9 years between themSo Age of B will be ==> (x-9)After 10 yearsA will be twice the age of B before 10 yearsx + 10 = 2 ( x - 9 )x + 10 = 2x - 1828 = xmeans now Age of A==> x = 28After 10 years i.e. Age of A will be 38, which is 2(x-9) ==> 2 X 19Means now age of B is (x-9)==> 19Ans is Age of B (now) >>> 19 A Bnow 28 19after 1o years 38 29

Dear Trivani

Please check the answer and reply me back about the question

Regards

Ans:

A+10=2(B-10) &

A-B=9 i.e. A=B+9,

now, putting it in earlier eqn.

B+19=2B-20

so B=39,

after 10 years B will be 39+10=49.

Ans =49

let the current age of A and B is  x and y.

so according to question

  after 10n yrs the age of A becomes twice the age of B before 10 years so---

        X+10=2(Y-10)

==> X-2Y=-30   Eqn-1

according to second condition the difference b/w there age is---9 yrs

X-Y=9  Eqn-2

now solving equation 1 and equation 2 the result is.....

age of A is 48 and of B is 39

A+10=2(B-10)

& A-B=9

so    A-2B=-30
       A-B=9       

         -B=-39

       so B=39+10
            B=49

According to given statement A+10=2(B-10) and also given that DIFFERENCE IS 9 then A-B=9 OR B-A=9 then problem is as follows substitute in the above A=B+9 then

B+19=2B-20 then

B=39

OR

If we consider

B-A=9 then

B=A+9 then

B+1=2B-20 then

B=21

(A+10)=2(B-10)
=>   A-2B=-30
and   A-B=9
so the answer is 58

49 years

sorry gys my 1st answer was wrong it is actually a's age after 10 years

let A's and B's present age be a,b years respectively.

then a-b=9--->1

a+10=2(b-10) ie. a-2b=-30--->2

1-2=>

 b=39;

so the age of B after 10 years will be 49

B will be of 49 yrs after 10 yrs

A+10=2(B-10)
=>A-2B=-30
A-B=9
so substituting A-B=9 in A-2B=-30
we get -B=-39
so , after 10 yrs B=39+10=49

Letpresent ages be'a' and 'b'.
after 10 yrs A's age will be a+10
and that of B will be b+10

age of B before 10 yrs = b-10

so given condition is
a+10=2(b-10)

second condition is
a-b=9

solving these two equations we get
b=39

so after 10 yrs B's age will be 39+10=49

A's age=9, B's age=38