Aptitude - After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet

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After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years between them then what is the age of B after 10 years

49a

Total Answers and Comments: 23

Last Update: November 08, 2009

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June 17, 2005 15:33:06

Sandeep Kumar

RE: After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet...

A+10 2(B-10)

&

A-B 9 i.e. A B+9

now
putting it in earlier eqn.

B+19 2B-20

so B 39

after 10 years B will be 39+10 49.

Ans 49

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June 18, 2005 03:10:49

TRIVENI

RE: After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet...

please send me the solution for this problem

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July 07, 2005 04:59:23

kavita kanyal

RE: After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet...

There will be two anwers as the difference is given. It's not given specifically that
A-B 9 or B-A 9

With A-B 9 :
eqns will be: 2B-A 30
and A-B 9
it will give B 39
hence Ans 39+10 49

With B-A 9 :

eqns will be: 2B-A 30
and B-A 9
hence B 21
hence Ans 21+10 31

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July 17, 2005 00:17:06

Here

RE: After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet...

two answers
1. If A 12 then B 21
2. If A 48 then B 39

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July 17, 2005 00:19:09

Here

RE: After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet...

thus 10 years later B will either be 49 or 31

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September 05, 2005 13:25:29

GAURAV RASTOGI

RE: After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet...

let the age of b x
let the age of a x-9
then the equation is
(x-9) x
after 10 years in a and before ten years in b
new equation will be
(x-9+10) 2(x-10)
then
the value of x 21 years
and after 10 years will be 31 years

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December 17, 2005 05:23:38

RAJESH

RE: After 10 years A will be twice the age of B...

let present age of a & b is 'A' 'B' respectively.after 10 yrs age of 'a' is A+10;before 10 yrs age of b is B-10.

given that A+10 2*(B-10)

and A-B 9

by solving above two we get B 39;

so after 10 yrs the age of b is 49

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February 25, 2006 08:53:13

VIKRAM MAJJARI

RE: After 10 years A will be twice the age of B...

answer:49let A's present age xAfter 10 years A's age 10+xLet B's age before 10 years y-10(present age y)a/c to problem 10+x 2(y-10) >x-2y -30--------------1st eq.alsox-y 9----------------------2nd eqsolving 1st and 2nd eqwe get x 48 and y 39so B's age after 10 years is y+10 i.e; 39+10 49

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April 07, 2006 03:54:43

sunitha

RE: After 10 years A will be twice the age of B...

the answer is........

B's age after 10 years will be

31 if B-A 9 is taken

or 49 if A-B is taken

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April 08, 2006 09:47:10

#10

shravani

RE: After 10 years A will be twice the age of B...

Let the age of A now is X.

age of B X-9.

Aft 10 yrs A s age x+10.

B4 10 yrs B s age x-19.

Given Xx+10 2X-38

This gives X 48

A s age 48 now. B s age 39 now.

After 10 yrs B's age will be 49.

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