Aptitude - After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet

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After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years between them then what is the age of B after 10 years

49a

Total Answers and Comments: 22

Last Update: June 30, 2008

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May 30, 2005 09:30:53

suresh

RE: After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet...

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June 17, 2005 15:33:06

Sandeep Kumar

RE: After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet...

A+10=2(B-10)

&

A-B=9 i.e. A=B+9,

now,
putting it in earlier eqn.

B+19=2B-20

so B=39,

after 10 years B will be 39+10=49.

Ans =49

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June 18, 2005 03:10:49

TRIVENI

RE: After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet...

please send me the solution for this problem

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July 07, 2005 04:59:23

kavita kanyal

RE: After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet...

There will be two anwers as the difference is given. It's not given specifically that
A-B=9 or B-A=9

With A-B=9 :
eqns will be: 2B-A=30
and A-B=9
it will give B=39
hence Ans=39+10=49

With B-A=9 :

eqns will be: 2B-A=30
and B-A=9
hence B=21
hence Ans=21+10=31

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July 17, 2005 00:17:06

Here

RE: After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet...

two answers
1. If A= 12, then B=21
2. If A= 48, then B= 39

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July 17, 2005 00:19:09

Here

RE: After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet...

thus, 10 years later, B will either be 49 or 31

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September 05, 2005 13:25:29

GAURAV RASTOGI

RE: After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years bet...

let the age of b=x
let the age of a = x-9
then the equation is
(x-9)=x
after 10 years in a and before ten years in b
new equation will be
(x-9+10)=2(x-10)
then
the value of x =21 years
and after 10 years will be 31 years

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December 17, 2005 05:23:38

RAJESH

RE: After 10 years A will be twice the age of B...

let present age of a & b is 'A','B' respectively.after 10 yrs age of 'a' is A+10;before 10 yrs age of b is B-10.

given that A+10=2*(B-10)

and A-B=9

by solving above two we get B=39;

so after 10 yrs the age of b is 49

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February 25, 2006 08:53:13

VIKRAM MAJJARI

RE: After 10 years A will be twice the age of B...

answer:49let A's present age=xAfter 10 years A's age=10+xLet B's age before 10 years =y-10(present age=y)a/c to problem,10+x=2(y-10)=>x-2y=-30--------------1st eq.alsox-y=9----------------------2nd eqsolving 1st and 2nd eqwe get x=48 and y=39so B's age after 10 years is y+10 i.e; 39+10=49

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April 07, 2006 03:54:43

#10

sunitha

RE: After 10 years A will be twice the age of B...

the answer is........

B's age after 10 years will be

31 if B-A=9 is taken

or 49 if A-B is taken

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