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# After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years between them then what is the age of B after 10 years

49a

This question is related to Accenture Interview
Sandeep Kumar

Answered On : Jun 17th, 2005

A+10=2(B-10)

A-B=9 i.e. A=B+9,

now,
putting it in earlier eqn.

B+19=2B-20

so B=39,

after 10 years B will be 39+10=49.

Ans =49

TRIVENI

Answered On : Jun 18th, 2005

please send me the solution for this problem

kavita kanyal

Answered On : Jul 7th, 2005

There will be two anwers as the difference is given. It's not given specifically that
A-B=9 or B-A=9

With A-B=9 :
eqns will be: 2B-A=30
and A-B=9
it will give B=39
hence Ans=39+10=49

With B-A=9 :

eqns will be: 2B-A=30
and B-A=9
hence B=21
hence Ans=21+10=31

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Here

Answered On : Jul 17th, 2005

1. If A= 12, then B=21
2. If A= 48, then B= 39

Here

Answered On : Jul 17th, 2005

thus, 10 years later, B will either be 49 or 31

GAURAV RASTOGI

Answered On : Sep 5th, 2005

let the age of b=x
let the age of a = x-9
then the equation is
(x-9)=x
after 10 years in a and before ten years in b
new equation will be
(x-9+10)=2(x-10)
then
the value of x =21 years
and after 10 years will be 31 years

RAJESH

Answered On : Dec 17th, 2005

let present age of a & b is 'A','B' respectively.after 10 yrs age of 'a' is A+10;before 10 yrs age of b is B-10.

given that A+10=2*(B-10)

and A-B=9

by solving above two we get B=39;

so after 10 yrs the age of b is 49

VIKRAM MAJJARI

Answered On : Feb 25th, 2006

answer:49let A's present age=xAfter 10 years A's age=10+xLet B's age before 10 years =y-10(present age=y)a/c to problem,10+x=2(y-10)=>x-2y=-30--------------1st eq.alsox-y=9----------------------2nd eqsolving 1st and 2nd eqwe get x=48 and y=39so B's age after 10 years is y+10 i.e; 39+10=49

sunitha

Answered On : Apr 7th, 2006

B's age after 10 years will be

31 if B-A=9 is taken

or 49 if A-B is taken

shravani

Answered On : Apr 8th, 2006

Let the age of A now is X.

age of B=X-9.

Aft 10 yrs As age =x+10.

B4 10 yrs Bs age =x-19.

Given, Xx+10=2X-38

This gives X=48

As age 48 now. Bs age 39 now.

After 10 yrs B's age will be 49.

anna

Answered On : Jun 26th, 2006

Let present age be A= x yr, B = y yr. Since A is Twice theage of B at some point A is older than Bx-y = 9x+10 = 2 (y-10)y = 39 present age. After 10 yr B's age = 49

pramod reddy

Answered On : Dec 26th, 2006

We get two values for B.We are given only the difference between A & B,But not who is older.So, the difference can be (A-B) or (B-A).Hence, we get B values as 39 & 21 respectively. NOw, just go back to the question and verify to check the required conditions.

The answer, i.e age of B after 10 years is 49.

yogeshgurav007

Answered On : Feb 7th, 2007

After 10 years A will be twice the age of B before 10 years.and now if the difference is 9 years between them then what is the age of B after 10 yearsConsiderAge of A is ==> xnow if the difference is 9 years between themSo Age of B will be ==> (x-9)After 10 yearsA will be twice the age of B before 10 yearsx + 10 = 2 ( x - 9 )x + 10 = 2x - 1828 = xmeans now Age of A==> x = 28After 10 years i.e. Age of A will be 38, which is 2(x-9) ==> 2 X 19Means now age of B is (x-9)==> 19Ans is Age of B (now) >>> 19 A Bnow 28 19after 1o years 38 29

Munish Jain

Answered On : Feb 8th, 2007

Dear Trivani

Regards

Ans:

A+10=2(B-10) &

A-B=9 i.e. A=B+9,

now, putting it in earlier eqn.

B+19=2B-20

so B=39,

after 10 years B will be 39+10=49.

Ans =49

puja

Answered On : Apr 23rd, 2007

let the current age of A and B is  x and y.

so according to question

after 10n yrs the age of A becomes twice the age of B before 10 years so---

X+10=2(Y-10)

==> X-2Y=-30   Eqn-1

according to second condition the difference b/w there age is---9 yrs

X-Y=9  Eqn-2

now solving equation 1 and equation 2 the result is.....

age of A is 48 and of B is 39

soujanya

Answered On : Jun 30th, 2007

A+10=2(B-10)

& A-B=9

so    A-2B=-30
A-B=9

-B=-39

so B=39+10
B=49

c.praveen sagar reddy

Answered On : Aug 26th, 2007

According to given statement A+10=2(B-10) and also given that DIFFERENCE IS 9 then A-B=9 OR B-A=9 then problem is as follows substitute in the above A=B+9 then

B+19=2B-20 then

B=39

OR

If we consider

B-A=9 then

B=A+9 then

B+1=2B-20 then

B=21

(A+10)=2(B-10)
=>   A-2B=-30
and   A-B=9

49 years

sorry gys my 1st answer was wrong it is actually a's age after 10 years

SKumarVembani

Answered On : Jun 30th, 2008

let A's and B's present age be a,b years respectively.

then a-b=9--->1

a+10=2(b-10) ie. a-2b=-30--->2

1-2=>

b=39;

so the age of B after 10 years will be 49

B will be of 49 yrs after 10 yrs

A+10=2(B-10)
=>A-2B=-30
A-B=9
so substituting A-B=9 in A-2B=-30
we get -B=-39
so , after 10 yrs B=39+10=49

mdeulkar

Answered On : Dec 20th, 2009

Letpresent ages be'a' and 'b'.
after 10 yrs A's age will be a+10
and that of B will be b+10

age of B before 10 yrs = b-10

so given condition is
a+10=2(b-10)

second condition is
a-b=9

solving these two equations we get
b=39

so after 10 yrs B's age will be 39+10=49

pktamilselvi

Answered On : Jan 10th, 2011

A's age=9, B's age=38