In pure milk if 20% replaced by water and in this again 20% is replaced by water and again 20% is replaced by water then what is the proportion of milk in that mixture

51.2%

52.2

just deduct 20% from 100 = 80, 
 
again reduce 20% of 80 from 80 = 64, 
 
again subtract 20% of 64 from 64 = 51.2  
 
Ans = 51.2 %

Ans 
(0.8*0.8*0.8)*100 = 51.2

Ans: 51.2%

Ans : 44%

Let us say we have 100 ml of milk initially.

Now each time we increase the volume by adding 20% water to the new solution.

First time we add 20% of 100 ml = 20ml. Now new volume = 120
Next time we add 20% of 120 ml = 24ml . Now new volume = 144
Third time we add 20% of 144ml = 28.8. Now new volume = 172.8.

Now the percentage of milk = 100/172.8*100 = 58.07

The volume of the mixture doesn't change because it is given that milk is getting REPLACED with water....

hence the ans should be 51.2%

Water is replaced, not added.

Pure milk - 100
20% replaced by water. so, it bcomes 80:20=4:1
again 20% replaced.so, 64:36=2:1
again 20% replaced. so, 51.2:48.8

The options are a) 40% b) 90% c) 51.8% d) 58.2% andthe right answer is 58.2%

The proportion of milk in t his mixture is 2:3

Given as Pure milk - 100%

20 perentage replaced by water. so it bcomes 80:20 . i.e, >>4:1
again 20 replaced.( kindly note that this replacement is done from 100 percentage of milk which already given, not from the 80 percentage ). Therefore the ratio become 60:40 >>>3:2
again 20 percentage replaced. so it become 40:60 >>>>2:3

Therefore we can conclude that give milk turns into 40 percentage of milk and 60 percentage of water>>>02:03

let pure milk b 1oo

answer is 51.2