There are 76 persons. 53 can read hindu,46 can read times,39 can read deccan and 15 can read all.if 22 can read hindu and deccan and 23 can read deccan and times then what is the number of persons who read only times and hindu

No it must be 16.... 
Since H+D=22 
T+D=23 
ALL=15 
then 76=22+23+15+(H+T) 
H+T=76-60=16... 
Any one please comment.....

Sorry friends  
but the correct answer is 17

16 makes sense

correct ans is 17.

To=H+T+D-HT-TD-HD+TDH 
76=53+46+39-X-22-23+15 
76=108-X 
X=108-76 
HT=32 
 
HT=32 -15 
HT=17.,

Correct answer is 17, not 18

Answer is 17

aUbUc=(a+b+c)-(a^b)-(B^c)-(c^a)+(a^b^c) 
 
U union 
^ intersection

Answer is 17>u can try by making vann dia or by using 
 
(aubuc)=a+b+c-(a^b)-(a^c)-(b^c)+(a^b^c)

n(H u T u D) = n(H) + n(T) + n(D) + n(H n T n D) - n(H n D) - n( T n D) - n(H n T)

--> 76 = 53+46+39+15 - 22 - 23 - x

--> 76 = 153 - 55 - x

--> x = 153 - 131

--> x = 22.

So, number of people who can read only Hindu and Times is 22. 

n(H u T u D) = n(H) + n(T) + n(D) + n(H n T n D) - n(H n D) - n( T n D) - n(H n T)--> 76 = 53+46+39+15 - 22 - 23 - x--> 76 = 153 - 45 - x--> x = 153 - 121--> x = 32.

Total no of persons should be 72, for the problem to make sense.

Test it using venn daigram.

Breakdown-

only hindu- 10,only times- 2,only deccan- 9

only hindu and deccan-7,only deccan and times-8,

Answer - only hindu and times-21

H+D=22H+D+T=15H+T=xH=53thereforeH=(H+D)+(H+D+T)+(H+T)53=22+15+xx=16

guys,think!!

answer is 32,the method by kalpana is the right one.. barani was also right but out a 55 where it shud be 45 so answer got,22 was wrong.. good effort by everyone..

the argument continues???

jack sparrow

AUBUC = A + B + C - AUB - BUC  - CUA + 3(A^B^C)

76= 53+46+39-22-23-TH + 3(15)

CALCULATE HT

the correct answer is 24.........

n(HuTuD)=n(H)+n(T)+n(D)-n(HnD)-n(DnT)-n(TnH)+n(HnTnD)

76=53+46+39-22-23-n(TnH)+15

76=153-45-n(TnH)

n(TnH)=153-45-76

n(TnH)=153-121

n(TnH)=32

ANS=32

It is a straight forward problem with the answer being 17...Add up all factors and equate to 76

by using vein diagram the answer is 17 vein diagram is easy method to calculate this type of problems

i think using venn diagram gives u 16......check it out......

hey guys

did u notice they havnt clearly mentioned that 22 ppl read ONLY indu and times

this could include the ppl who read all the 3 papers

else d ans is 22

its 16..acc tp prob rule-53=76-22-x+15x=16

ans is 17

I would like to share my answer and approach, even if I may not take the accenture exam.Those who speak Hindu and Deccan (HD) include those who speak all the languages. When we subtract (22 (HD) -15 (ALL)), we get the people who speak only the HD combination. We do the same thing (23 (DT) -15 (ALL)) for people who speak only Deccan and Times (DT). This leads us to a subtraction of these people from the greater whole. For the Hindu speakers, we get (53 (H) -15 (ALL) -7 (HD)=) 31 candidates who could either be only Hindu speakers or Hindu-Times speakers. For the Times speakers, we get (46 (T) -15 (ALL) -8 (DT)=) 23 candidates. We figure that there is some intersection between these figures. So we subtract those non-candidates from the running by subtracting all Deccan speakers from the total (76 (tot) -39 (D)=37(left)). The total is the number of people we have left who can speak either Hindu, Times or Hindu-Times only. We add the possible candidates up (23+21) and from the total, subtract the people we have left (54-37(left)). The answer I got is 17. When we add all of the kinds of speakers up:ALL DECCAN HINDU TIMES DEC/HIN DEC/TIM HIN/TIM TOTAL15 9 14 6 7 8 17 76You get the correct total.

 Total(T) is given 73
Hindu readers,n(H)= 53

TOI readers, n(toi)= 46
deccan reader , n(D)=39
and n(H+TOI+D)=15
76= 53+46+38-x-22-23+15
x = 32 ans

right answer is 17.

Correct answer:
only H:14
only T:6

The no. of persons reading H n T are 32(53+46+39-22-23-76+15)

Then persons reading only H(53-32-22+15)=14
only T(46-32-23+15)=6

I calculate the answer to be 32 !!! = 15 (given by the problem) + 17 (calcd as 76-23= 37 = (31-y) + (23 -y) + y , where y represented the missing piece between H&T; this piece would be added to 15, so as to represent the ENTIRE H&T section - which is the question..

I used part Venn diagrams to portay it, and then equations to do the final calc (its been a while since I took a discrete math class..so my answer wasnt elegant).

the correct ans is 17

Assume X persons read only times and hindu.

So 76 equal to 53+46+39-(22+23+x)+15.

solve the above we will get x equal to 32. 

32 can read times and hindu. so, 32-15 ie, 17 can read only times and hindu.

Assume X persons read times and hindu.

So 76 equal to 53+46+39-(22+23+x)+15.

solve the above we will get x equal to 32.

32 can read times and hindu. so 32-15 ie 17 can read only times and hindu.

Hi!  you are right. The answer must be 16.

Given details are,

Total number of Readers = 76

Readers of Hindu & Deccan = 22
Readers of Times and Deccan = 23
Readers who read all = 15

And we have to find out the total number of readers who readk ONLY time and Hindu. Therefore the formula is,

Only Time and Hindu Readers = Total number of Readers - ( Reader of Hindu and Deccan + Readers of Time and Deccan + readers who reads all )

i.e,  Only T & H Readers ( X )= 76 - ( 22+23+15)

==>  X= 76- 60 ===>> 16

We can conclude that the ONLY readers of Time & Hindu  is 16


Many thanks
Muhammed Kareem

using union law (aubuc)=a+b+c-(anb)-(anc)-(bnc)+(anbnc)

Ans:17

Total=d+t+h-dt-th-hd+dth
76=39+46+53-23-22-ht+15
76=108-ht
ht=108-76
ht=32

We want only times and hindu,so we subtract the value of all papers read is 15 from ht.

so the ans is 32-15=17.