Aptitude - (998-1)(998-2)(998-3)…………..(998-n)=------- when n>1000

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(998-1)(998-2)(998-3)…………..(998-n)=------- when n>1000

zero

Total Answers and Comments: 14

Last Update: March 26, 2009

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June 17, 2005 14:40:29

Sandep Kumar

RE: (998-1)(998-2)(998-3)…………..(998-n)=------- when n>1000

It is surely 0 as when n 998

then 998-998 0 so all is 0

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June 26, 2006 09:51:31

Akash

RE: (998-1)(998-2)(998-3)…………..(998-n)=------- ...

Zero Because at some point n 998 and 998-998 0

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August 13, 2006 11:43:18

thiyagarajanganesan

Member Since: August 2006 Contribution: 4

RE: (998-1)(998-2)(998-3)…………..(998-n)=------- ...

the questionr answer is wrong.how 998 comes when n is greater than 1000.explain me please.

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November 30, 2006 22:29:44

RE: (998-1)(998-2)(998-3)…………..(998-n)=------- ...

if u take 998 common then eq. will be

(998)^n(1-1)(1-2)....................(1-n) (998)^n(0)(-1)......

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March 09, 2007 02:25:51

Hemanshu

Answer is 55

Ans 55

Here are all the combinations

009 019 029 039 049 059 069 079 089 099
109 119 129 139 149 159 169 179 189
209 219 229 239 249 259 269 279
309 319 329 339 349 359 369
409 419 429 439 449 459
509 519 529 539 549
609 619 629 639
709 719 729
809 819
909

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April 17, 2007 04:49:06

ram

RE: (998-1)(998-2)(998-3)…………..(998-n)=------- ...

as n>1000.in the series as u go there will be (998-998) 0 and the whole product is zero.1 2 3 .......................................998 999 1000.

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May 07, 2007 07:32:01

Boopalan

RE: (998-1)(998-2)(998-3)…………..(998-n)=------- ...

The condition given in the question is n>1000 therefore the consideration n 998 is not valid.

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May 12, 2007 02:26:37

kiran

RE: (998-1)(998-2)(998-3)…………..(998-n)=------- ...

The above problem result is zero bcz n 998 in one position.
our condition is n>1000
but we give up to so on (998-1)(998-2)(998-3)(998-4)………..(998-998)(998-999)(998-1000) (998-n)
n>1000
1 is not greater then 1000
how it is possible (998-1)

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May 12, 2007 03:05:11

MANISHA

RE: (998-1)(998-2)(998-3)…………..(998-n)=------- ...

As n is greater than 1000. but you have not observed that n is getting reduced by one in each step. so at certain point n will become 998. And 998-998 will be '0'. Therefore the answer is '0'.

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July 20, 2007 13:20:05

#10

sameer2386

Member Since: April 2007 Contribution: 3

RE: (998-1)(998-2)(998-3)…………..(998-n)=------- ...

The Q is (998-1)(998-2)(998-3)…………..(998-n) ------- (n>1000)

as u solve it u will be in a position that
(998-1)(998-2)(998-3)…………..(998-998)(998-999)(998-1000)------(998-n)

so means at some position it is (998-998)
means answer will be zero

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