Sandep Kumar

• Jun 17th, 2005

 

It is surely 0 as when n=998, 
 
then 998-998 =0 so all is 0

Akash

• Jun 26th, 2006

 

Zero Because at some point n = 998 and 998-998 =0

thiyagarajanganesan

 Profile Answers by thiyagarajanganesan 

• Aug 13th, 2006

 

the questionr answer is wrong.how 998 comes when n is greater than 1000.explain me please.

ss

• Nov 30th, 2006

 

if u take 998 common then eq. will be

(998)^n(1-1)(1-2)....................(1-n)=(998)^n(0)(-1)......

=0

Hemanshu

• Mar 9th, 2007

 

Ans == 55

Here are all the combinations

009 019 029 039 049 059 069 079 089 099
109 119 129 139 149 159 169 179 189
209 219 229 239 249 259 269 279
309 319 329 339 349 359 369
409 419 429 439 449 459
509 519 529 539 549
609 619 629 639
709 719 729
809 819
909

ram

• Apr 17th, 2007

 

as n>1000.in the series as u go there will be (998-998)=0 and the whole product is zero.1, 2,3 .......................................998,999,1000.

Boopalan

• May 7th, 2007

 

The condition given in the question is n>1000, therefore the consideration n=998 is not valid.

kiran

• May 12th, 2007

 

   The above problem result is zero bcz n=998 in one position.
             our condition is n>1000
  but we give up to so on (998-1)(998-2)(998-3)(998-4)………..(998-998)(998-999)(998-1000) (998-n)
                      n>1000
1 is not greater then 1000
  how it is possible (998-1)

MANISHA

• May 12th, 2007

 

As n is greater than 1000. but you have not observed that n is getting reduced by one in each step. so at certain point n will become 998. And 998-998 will be '0'. Therefore the answer is '0'.

sameer2386

 Profile Answers by sameer2386 

• Jul 20th, 2007

 

The Q is (998-1)(998-2)(998-3)…………..(998-n)=------- (n>1000)

as u solve it u will be in a position that
(998-1)(998-2)(998-3)…………..(998-998)(998-999)(998-1000)------(998-n)

so means at some position it is (998-998)
means answer will be zero

Rahul Kukreti

• Aug 4th, 2007

 

The above question means that n starts from '1' but have value atleast upto 1000 or more than that,
so question is correct

ashishsurana

 Profile Answers by ashishsurana 

• Mar 4th, 2008

 

Does anyone really needs some explaination for this question????
Simple:- 998-998=0

sakhya

 Profile Answers by sakhya 

• Mar 8th, 2008

 

When n=998,it becomes 998-998=0;so ans will be 0

vijay pal saharan

 Profile Answers by vijay pal saharan 

• Mar 25th, 2009

 

I am surprised, how come these people answer this question.
Because unless the value of n is given no mathematician can solve this question.
even no one can even guess whether the answer is -ve or +ve.
Some people give answer zero, It's really amazing...
It is already given that n>1000.
Then the answer will never be zero.
The conclusion is that answer may be calculated in terms of n but not in digits.

samir316

 Profile Answers by samir316 

• Jan 18th, 2010

 

The answer is ZERO.
Because  while increasing n 4rm 1 to 1000 once it will be 998 and hence the result of (998-n) will be zero and since all the terms are multiplied by each ohter anythng multiplied by zero is zero hence the answer.

amrita kumari

• May 2nd, 2015

 

(999)2-(998)2

sandeep kumar

• Aug 22nd, 2015

 

Ans --0 because (998-998)=0 are present in the series and all series are multiple form