A can do in 6 day and B can do in 8 and C can do in 12 days but b left after working for 6 days for how many no of day A and C should work

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xxx

  • Jul 12th, 2005
 

B has finished 6/8 th of the total work / work remaining is 1/4 ( A and C together can work 1/6 + 1/12) = 1/4 per day , hence the answer is 1 day

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sivanarayan

  • Jan 12th, 2006
 

lets assume both can do remaining work in x daysx(1/12 + 1/6) = (1-6/8)x= 1; the number of days they together have to work to complete the remaining work is 1 day

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Krovatkin

  • Sep 18th, 2010
 

Had they completed the work in less than 6 days, B wouldn't have worked for 6 days...
The question implies that B worked alone for 6 days and then A and C picked up where he left off.

I believe the answer given by pravesh28 is correct...

B did 6/8 of the work or 3/4

(1/6+1/12)*x = 1-3/4

1/4x=1/4

x = 1

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The problem did not indicate that it is a group work..  So I assumed that A,B and C are working individually ( I might be wrong..)  so, if B left after working for 6 days: the remaining working days left to A and C are:
    A - 0 days
    C - 6 working days remaining
The number of working days of A and C will  not affect the absence of B
since they are working individually...  Ofcourse, the answer will be different if it is a group work since the  no. of working days efficiency of A, B and C will be pro rated to the total number of working days needed to be done, less the absence of B after just 6 days...

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