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Find the minimum value of 3X+4Y if (X*X*X)(Y*Y)=6

  
Total Answers and Comments: 1 Last Update: May 11, 2007     Asked by: kirupa 
  
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May 11, 2007 13:24:36   #1  
kmaheshkumar        

RE: Find the minimum value of 3X+4Y if (X*X*X)(Y*Y)=6
Given

X^3*y^2 6

Y sq is positive > X cube is positive >X is positive >Y is positive



Factors of 6 are 1 2 3 6

Values for X cube 1 2 3 6

Values for Y square 6 3 2 1



The least values are X root cube 3 and Y sqroot 2 since 3x+4y

Thus

Minimum value of 3X+4Y is 3*cuberoot3 + 4*sqroot2



Hence the Ans


 
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