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Latest 2007 Quant. Problems of TCS
: Pls solve these

1. Which will give good standard deviation?
a). 4,0,-4,0,4 b) 4,-4,4,-4,4 c) 4,4,4,4,4

2. What is the value of the following expression M(373,5)+T(7.7)+R(4.4)-T(3.6)
Where M- MODULAS R- ROUNDOFF T- TRUNCATE

3. If A, B, C are the mechanisms used separately to reduce the wastage of fuel by 30%, 40%, 10%.What will be the fuel economy if they were used combine?
1.68.4 2.62.2 3.58 4.27

4. Which of the following straight lines are perpendicular to each other?
1)2x+y=8 2)x=4 3)y=6 4)2y=x+3
a)1, 3 b)2, 3 c)1, 4 d)3, 4 e)None

5. 6. Which of the following is exact power of 4?
a) 4192 b) 2340 c) 4096



  
Total Answers and Comments: 5 Last Update: September 23, 2007     Asked by: Kelly812 
  
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March 05, 2007 08:11:35   #1  
siva@anna univ        

RE: Latest 2007 Quant. Problems of TCS
for the third question : find the average of three .ie (30+40+10)/3 26.6 27
for the fourth : second is correct.( x 4 y 6 in the graph is normal toeach other)
for the fifth : second is correct .. sum of the last two digit must be divided by 4

 
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March 05, 2007 09:16:04   #2  
sriharibabu.c        

RE: Latest 2007 Quant. Problems of TCS
which has the more negative signs that should be give the highest standard deviation
 
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March 13, 2007 06:48:38   #3  
shiva prasad        

RE: Latest 2007 Quant. Problems of TCS
the answer for the four power sum is C........... powers of four always end with only 4 and 6......... it cannot be 'b'.......
 
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March 20, 2007 15:57:20   #4  
chida        

RE: Latest 2007 Quant. Problems of TCS

Hi to all
The answer of first question is option a bcoz it has 2 zeros and a negative number.
2.m(373.5) 3 t(7.7) 7 r(3.6) 4 like that

ans is 12

3.and 4as given above

5.4096 2 to the power 12 4 to the power 6

ans 4096


 
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September 23, 2007 09:03:37   #5  
hemant rawat        

RE: Latest 2007 Quant. Problems of TCS

hiii frnds

answer to question number fuel economy is
let say x is the original amount of fuel used without any economy
then economy of 30 means fuel used is x(1-30/100) x(70/100)
now further economy of 40 means fuel used is x(70/100)(60/100)
further economy of 10 means fuel used is x(70/100)(60/100)(90/100).............(1)

so let take x 100 (original fuel without any economy)
so from expression (1) we hav
finally fuel used after economy 37.8

therefore

fuel saved is 62.2 (which is fuel saved wen our original fuel i.e x is 100 hence it represent percent also and which is our final answer )

answer to standard division is
Xbar Mean of all given values
S.D sqrt[{SQUARE(X1-Xbar)+SQUARE(X2-Xbar)+SQUARE(X3-Xbar)+........}/N]

so from formula u will notice dat one who have smaller mean(mostly 0) will hav good S.D and that is possible only when values given cancels each other

so just observe the value n u will find S.D


with best wishes

i hope my answers r rite plzz comment if i m wrong


 
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