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 QTP  |  Question 349 of 650    Print  
In one of the popup window,
1.I have recorded two edit fields by selecting them from a drop down box and after I have selected the options, 'INSERT' field need to appear. But when I am running those steps the option that I have selected is not shown up but the default options are shown up and 'INSERT' button too does not shown up. How to make sure that the selected fields are displayed along with the 'INSERT' link.
When I am recording it is recorded as:
Browser().Page().WebTable().WebElement(Option name that I have selected).click

2. How to differentiate between two or three links with same name, like "DELETE", when the TYPE is None and not Index. When I am putting it in a loop, only one link gets deleted which is associated to one row. For other rows the 'Object not found' message is displayed


  
Total Answers and Comments: 2 Last Update: February 11, 2007     Asked by: Sujatha Kandikonda 
  
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February 07, 2007 02:24:32   #1  
msusmitha Member Since: November 2006   Contribution: 31    
RE: In one of the popup window, 1.I have recorde...
hi thi is susmithado u know the use of pop up windows.it is used for overcoming the problematic situation in ur eg u r nt getting the insert buttons enabled properity. for that u have to check the enable properity first by using the standard check point and then if u want to click on that button u specify the object state, in that u have to write a function call which is having the state of that bject. do thatautomatically u will get the solution.for second one u r using the links which is having the same name. while running u r getting that first row passes after that your test fails that means in the first row u deleted the link how it can belinked with net one because it is having the same name.i think u understoodmadhav_sus@yahoo.co.in
 
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February 10, 2007 18:40:15   #2  
Bhamini        
RE: In one of the popup window, 1.I have recorde...
Hi,i am not able to understand the question correctly. but if i get it right, then you want to use the same object name, but itrs property's value change depending upon your previous selections.such as if you select option 1, then link1 is displayed,.



if option 2 is selected then link is 2. but instead of recording 2 objects (different links) you want to use one object.what you can do is, use the method SetTOProperty(). this method will set the test object's property value at runtime.what you can do is



If "you have selected option 1" Then

Browser("abc").Page ("abc").Link("abc").SetTOProperty "value", "link1"

Else

Browser("abc").Page ("abc").Link("abc").SetTOProperty "value", "link2"

End If




I have used value as an example. you have to specify the appropriate property and the second parameter is the name.



this should help.
 
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