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A software engineer starts from home at 3pm for evening walk. He walkspeed of 4kmph on level ground and then at a Speed of 3kmph on the uphill and then downhill at a speed of 6kmph to the level ground and then at a speed of 4kmph to the Home at 9pm.
what is the distance on one way?

  
Total Answers and Comments: 1 Last Update: June 14, 2005   
  
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June 14, 2005 02:44:40   #1  
Vivek Sharma        

RE: A software engineer starts from home at 3pm for evening walk. He walkspeed of 4kmph on level ground ...
The above question can be solved in 3 ways:

Approach 1:

Let the total time taken while travelling one way be: x
then
time taken to travel back is given by: 6 - x
We know that the distance travelled both the ways is same therefore
3.5(x) 5(6-x)
[ 3.5 (4 + 3) / 2 average speed while going upside. 5 is the average speed while coming back]
solving for x we get
x 3.5
Therefore
distance travelled 3.5 * 3.5 12.25 approx.
Total dist. travelled 12 * 2 24.

2. Short Cut Method:

We know that if a body travels a certain distance in x km/hr and then the same dist. again in y km/hr then the average speed of the body is given by:
2xy/x+y
Applying the above formula we can get the total average speed of the man through out the journey.
(2 * 3.5 * 5) / (3.5 + 5.0) 35 / 8.5 4.11 aprox.
total time taken to complete the journey 9 - 3 6 hrs.
therefore
total distance traveled 4 * 6 24.
one way distance 24 / 2 12

 
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