1/3 ed of the contents of a container evaporated on the 1st day. 3/4 th of the remaining contents of the container evaporated the second day. what part of the contents of the container are left at the end of the second day.
RE: 1/3 ed of the contents of a container evaporated o...
come to think of it logically i'll represent original content with this line below ------------------(no evap) ------------ (rem 2/3rd after one day) --- (rem 1/4th of previous 2/3rd at end of 2nd day i.e. 1/6 is left)
i'd say the result doesn't resemble 50 ? the 1/2 u r calculating is actually the amt evaporated on 2nd day 2/3 - [(3/4)*(2/3)] 1/2 of 'original' content.
RE: 1/3 ed of the contents of a container evaporated o...
1/6 is right.....
First day it is 1/3 tat gets evaporated...then after 1st day we have 1-1/3 remaining ie. 2/3 and on the 2nd day 3/4 of the remaining (2/3) gets evaporated ie.(2/3*3/4))