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 CTS  |  Question 74 of 86    Print  
Why Result is Different for
1)
int x=5;
int y;
y=++x + ++x + ++x
2)
int x=5;
int y=++x + ++x + ++x

  
Total Answers and Comments: 3 Last Update: May 30, 2008     Asked by: Prakash 
  
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January 23, 2007 09:14:21   #1  
machogamer Member Since: January 2007   Contribution: 3    

RE: Why Result is Different for1)int x=5;
In Type 1: Line 3 is treated as an expression and based on the Operator Precedence the increment [ ++ ] operatortakes precedence over summation [ + ] operator. Hence in the expression the increment operation is done first and then the summation operation is done thus the output of the expression will be 24 .In Type 2: Line 2 is treated as an assignment statement and is hence evaluated from left to right. Thus the value of ' y ' in this case will be 21.
 
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February 27, 2007 12:47:45   #2  
Remi        

RE: Why Result is Different for1)int x=5;
How does it sum up to 24?
 
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February 05, 2008 04:15:24   #3  
sauvik_36 Member Since: November 2007   Contribution: 1    

RE: Why Result is Different for1)int x=5;int y;y=++x + ++x + ++x2)int x=5;int y=++x + ++x + ++x
it gives 21 on both cases with javac and 24 on both cases wth turboc....
the result can be erratic there4... varies wth the compiler....

 
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