CTS - Why Result is Different for1)int x=5;int y;y=++x + ++x + ++x2)int x=5;int y=++x + ++x + ++x

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CTS | Question 74 of 85

Why Result is Different for
1)
int x=5;
int y;
y=++x + ++x + ++x
2)
int x=5;
int y=++x + ++x + ++x

Total Answers and Comments: 3

Last Update: May 30, 2008 Asked by: Prakash

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January 23, 2007 09:14:21

machogamer

Member Since: January 2007 Contribution: 3

RE: Why Result is Different for1)int x=5;

In Type 1: Line 3 is treated as an expression, and based on the " Operator Precedence " the increment [ ++ ] operatortakes precedence over summation [ + ] operator. Hence in the expression, the increment operation is done first, and then the summation operation is done, thus the output of the expression will be " 24 ".In Type 2: Line 2 is treated as an assignment statement, and is hence evaluated from left to right. Thus the value of ' y ' in this case will be 21.

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February 27, 2007 12:47:45

Remi

RE: Why Result is Different for1)int x=5;

How does it sum up to 24?

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February 05, 2008 04:15:24

sauvik_36

Member Since: November 2007 Contribution: 1

RE: Why Result is Different for1)int x=5;int y;y=++x + ++x + ++x2)int x=5;int y=++x + ++x + ++x

it gives 21 on both cases with javac and 24 on both cases wth turboc....
the result can be erratic there4... varies wth the compiler....

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