C - what is the output of following program?#includevoid main(){printf("%d%d",sizeof(NULL),sizeof(" "))

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what is the output of following program?
#include
void main()
{
printf("%d%d",sizeof(NULL),sizeof(" "));
}

Total Answers and Comments: 10

Last Update: November 19, 2009 Asked by: pavankishore

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Best Rated Answer

—

Submitted by: radhika

the #include must be completed else its syntax error,
NULL have to be declared(stdio.h)
if <stdio.h> is included the result is 22

Above answer was rated as good by the following members:
hydsarema

November 29, 2006 10:10:07

rohit khanna

RE: what is the output of following program?#inc...

an error will apper while compiling the program that function printf should have prototype

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0 1

Overall Rating: -1

February 02, 2007 01:22:30

Arwa Patel

RE: what is the output of following program?#inc...

The answer is 44..
As the space is an empty character and one the compiler counts one more character for the Null character constant '/0' And the space that Null takes in memory is 4 bytes same as int but this value depends on the Compiler that you use

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February 15, 2007 08:42:27

winny gupta

Member Since: February 2007 Contribution: 8

RE: what is the output of following program?#inc...

Since the file name ie stdio.h not included hence will give an error..

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March 23, 2007 04:59:15

radhika

RE: what is the output of following program?#inc...

the #include must be completed else its syntax error
NULL have to be declared(stdio.h)
if <stdio.h> is included the result is 22

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1 0

Overall Rating: +1

June 02, 2008 04:46:01

SpandanaMohan

Member Since: January 2008 Contribution: 12

RE: what is the output of following program?#includevoid main(){printf("%d%d",sizeof(NULL),sizeof(" "));}

Error..The printf stmt shld hav a prototype...

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August 26, 2008 05:55:14

mraghu

Member Since: August 2008 Contribution: 1

RE: what is the output of following program?#include void main(){printf("%d%d",sizeof(NULL),sizeof(" "));}

Error

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September 06, 2008 12:16:12

abhishek125

Member Since: June 2008 Contribution: 1

RE: what is the output of following program?#includevoid main(){printf("%d%d",sizeof(NULL),sizeof(" "));}

it will print : 2 2

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November 16, 2008 10:10:24

joejan

Member Since: November 2008 Contribution: 1

RE: what is the output of following program?#includevoid main(){printf("%d%d",sizeof(NULL),sizeof(" "));}

It is 2 2. If the there are 3 spaces in between the brackets output would be 2 3

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October 09, 2009 09:28:39

nirmal1989

Member Since: October 2009 Contribution: 1

RE: what is the output of following program?#includevoid main(){printf("%d%d",sizeof(NULL),sizeof(" "));}

If <stdio.h> is included it will print 42 which means sizeof null is 4 and that of char is 2.

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November 19, 2009 21:24:53

#10

daniel.raj.n

Member Since: May 2008 Contribution: 1

RE: what is the output of following program?#includevoid main(){printf("%d%d",sizeof(NULL),sizeof(" "));}

It depends on the memory model.

NULL will be defined as 0 or 0L ie as int or float. If the memory model is tiny small or medium then sizeof(NULL) will be equated to sizeof(0) which is sizeof(int) 2 bytes.
For other memory model itsvalue is 0L and so sizeof(0L) equals sizeof(long) 4 bytes.
and '' will be treated as a char and so its value is one byte.

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