Four Members A,B,C,D are playing a game .A person losing a game should double the amount of others .B,C,D are losing in order after three games .The amount after 3 games are A&B having 40,D is having 16&C 80. Each questions carry one mark: a) who started with small amount of money? b)who started with greatest amount of money? c)what amount did B have?
Total Answers and Comments: 7
Last Update: February 04, 2007 Asked by: VARALAKSHMI
RE: Four Members A,B,C,D are playing a game .A person ...
ansa) A started with small amount of money reason)He didn't lose any money so his initial amount is 40 which is least than allb)B reason)He is first person in losing the match....so he gave more money..c)b have 2616 reason)by calculation
RE: Four Members A,B,C,D are playing a game .A person ...
intial values of each player A - 5; B - 93; C - 54; D - 24.REASON 1) 'A' DID NOT LOSE ANY MATCH SO HIS MONEY GETS DOUBLE IN EACH GAME 5 --> 10 --> 20 --> 402) 'B' LOST THE FIRST GAME SO HE GAVE 5 TO A; 46 TO C; 32 TO D;A -->10; C--> 108; D--> 48 AND B--> 10 (TO ARRIVE AT B's VALUE ALWAYS REMEMBER TOTAL DOESN'T CHANGE. SO SUBTRACT A C D AMOUNTS WITH TOTAL(176))3) SIMILAR PROCEDURE FOR THE REMAINING TWO ROUNDS.A--> 20 --> 40B--> 20 --> 40C--> 40 --> 80D--> 96 -->16SO ANSWERS AREa) Ab) Bc) 93
