Aptitude - The size of a program is N. And the memoryoccupied by the program is given by M = square root of 100

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Aptitude | Question 69 of 147

The size of a program is N. And the memory
occupied by the program is given by M = square root of
100N. If the size of the program is increased by 1%
then how much memory now occupied ?

plz any one tell me,how to answer this....

Total Answers and Comments: 5

Last Update: May 28, 2008 Asked by: krithika

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October 10, 2006 01:45:50

kr vanitha

RE: The size of a program is N. And the memoryoc...

plz i need to answer that question thank u

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October 10, 2006 11:42:07

vchandm23

Member Since: September 2006 Contribution: 4

RE: The size of a program is N. And the memoryoc...

here M= sqrt(100N)

1N+100N=101N%

sqrt(101N)/10

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November 22, 2006 10:44:45

Mithila

RE: The size of a program is N. And the memoryoc...

M=sqrt(100N)

N is increased by 1%

therefore new value of N=N + (N/100)

=101N/100

M=sqrt(100 * (101N/100) )

Hence ,we get

M=sqrt(101 * N)

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February 17, 2008 00:07:19

priyat

Member Since: February 2008 Contribution: 2

RE: The size of a program is N. And the memoryoccupied by the program is given by M = square root of 100N. If the size of the program is increased by 1%then how much memory now occupied ?

0.2 is the ans

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May 28, 2008 08:30:23

chandradeepika

Member Since: May 2008 Contribution: 36

RE: The size of a program is N. And the memoryoccupied by the program is given by M = square root of 100N. If the size of the program is increased by 1%then how much memory now occupied ?

M1=sqrt(S1)=sqrt(100N)
S2=101%S1=1.01N
M2=sqrt(S2)=sqrt(100*(1.01N))=sqrt(101N)
% increase is :
= (((sqrt(101N)-sqrt(100N))/sqrt(100N))*100)
=(((sqrt(101)-10)/10)*100)%
=((10*sqrt(101))-100)%
=((10*10.05)-100)%
=(100.5-100)%
=0.5%

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