Diju Jacob

• Oct 18th, 2006

 

1 cost 50

other cost 150

REVANTH

• Oct 29th, 2006

 

let cost of cow A=x;

     cost of cow B=y;

given x+y=210;.........................................1

10% profit on A means he got x/10;

10% loss on B means he got -y/10;

given total profit =5%;

therefore x/10-y/10=5% of(210);

=>x-y=105;...............................................2

solving 1  &  2

we get x=157.2 , y=52.8;

=> cost of cow A=157.2  &  cost of B=52.8

Meera Nikhil

• Dec 22nd, 2006

 

actual price-> A,B

Selling price->Sa,Sb

Sa+Sb=210

combined profit-> 5%

So, A+B=200

Substitute for Sa+Sb=210,

[(200-B)+(200-B)10/100 ] +

[(200-A)-(200-A)10/100 ]=210

gets A=150

so B=50

S.P. Vijayanand

• Jan 8th, 2007

 

Original Price of the cows: (a + b) =210 - (5% of 210)

a + b= 210 - 10.5

a + b = 199.5 -------> (Eq.1)

a=199.5 - b & b = 199.5 - a

profit on a = 10% ie (199.5 - b)/10

loss on b = 10% ie (199.5 - a)/10

altogether former made a profit of 5%

so [(199.5 - b)/10] - [(199.5 - a)/10] = 10.5

  199.5 - b - 199.5 + a = 10 * 10.5

   a - b = 105 -----> (Eq.2)

solve Eqs (1) & (2)

a + b = 199.5

a - b = 105       Adding (1) & (2)

2a =  304.5 ==> a=152.25

subs in any one eq u'll get b = 47.25    so (152.25 + 15.225 (10% profit) + 47.25 - 4.725(10% loss) = 210

nayan

• Oct 17th, 2007

 

x1 and y1 are selling prise
x0 and y0 are  purchage cost
x1 +y1 =210 -----------------(1)
profit 10%
so (x1-x0) /x0=0.1
x1=1.1x0
loss 10% for other cow
so (y0-y1)/y0=0.1
y1=0.9y0
for both 5% profit
so ((x1+y1)-(x0+y0))/(x0+y0)=0.05
210/(x0+y0)=1.05
finally x0+y0=200--------------(2)
put x1 and y1 values in equation 1
0.9y0+1.1x0=210--------------(3)

solve equation 2 and 3
u will get x0=150 and y0=50

jayath419

 Profile Answers by jayath419 

• Jan 9th, 2008

 

the cows cost 117.75 and 82.25 resp.

rmsontakke

 Profile Answers by rmsontakke 

• Jan 22nd, 2008

 

He buys one cow for 50

&
other for 150 rs

anil24.danda

 Profile Answers by anil24.danda 

• Feb 20th, 2010

 

For example:
If each cow cost Rs: 100.
on one 10% profit i.e: 110.
on another 10% loss i.e: 90.
now he got total 200.
atlast he got 5% profit on both i.e: 5%200 = 10.
now total amount is 200 + 10 = 210.
then original cost is 100 each.

kartikhere

 Profile Answers by kartikhere 

• Sep 10th, 2010

 

Let the cp(cost price) of two cows be x,y respectively.

Then, sp (selling price) of cow1 would be x*110/100 (since the first cow earns a profit of 10%).

sp of cow2 - y*90/100 (cow2 makes a loss of 10%)

so by combining the sp of two cows we get :- (x*110/100 ) + (y*90/100) =210 ......eq(1

altogether he made a profit of 5% which means-- (x+y)*105/100= 210........eq(2

combining eq(1 & eq(2, we get

     11x+9y= 2100

        x+y=200

so..aftr solving we get x-150 and y=60( 210-150)..