struct out {
struct in{ char c;int d;}s1,p1;
}a1, pa1;

pa1 = &a1;
a1.p1 = &s1;
Which is incorrect?
a. a1.p1->c
b. pa1->p1->c
c. a1->p1
d. a1.s1.c

This question is related to TCS Interview

Asked by: Interview Candidate | Asked on: Sep 21st, 2006

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Guest

Answered On : Sep 26th, 2006

option c is wrong i.e. a1->p1. Because a1 is not a pointer, you can not refer its member through -> operator.

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winny gupta

Answered On : Feb 15th, 2007

View all answers by winny gupta

c is the wrong option as a1 is not a pointer variable

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naresh

Answered On : Feb 22nd, 2007

hi frns
the above one ans is c
because a1 can hold only the value of s1 but not its address value........
abd more over p1 cant be hold by a1 so the a1 cant become pointer to p1

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struct out {
struct in{ char c;int d;}s1,p1;
}a1, pa1;

pa1 = &a1;
a1.p1 = &s1;
Which is incorrect?
a. a1.p1->c
b. pa1->p1->c
c. a1->p1
d. a1.s1.c

Give your answer:

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