C - struct out {struct in{ char c;int d;}s1,*p1;}a1, *pa1;pa1 = &a1;a1.p1 = &s1;Which is incorrect?a. a1

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C | Question 83 of 87

struct out {
struct in{ char c;int d;}s1,*p1;
}a1, *pa1;

pa1 = &a1;
a1.p1 = &s1;
Which is incorrect?
a. a1.p1->c
b. pa1->p1->c
c. a1->p1
d. a1.s1.c

Total Answers and Comments: 3

Last Update: February 22, 2007 Asked by: diwakar

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option c is wrong i.e. a1->p1. Because a1 is not a pointer, you can not refer its member through -> operator.

Above answer was rated as good by the following members:
ratneshict

September 26, 2006 08:05:44

RE: struct out {struct in{ char c;int d;}s1,*p1;...

option c is wrong i.e. a1->p1. Because a1 is not a pointer, you can not refer its member through -> operator.

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Overall Rating: +1

February 15, 2007 08:47:01

winny gupta

Member Since: February 2007 Contribution: 8

RE: struct out {struct in{ char c;int d;}s1,*p1;...

c is the wrong option as a1 is not a pointer variable

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February 22, 2007 07:35:36

naresh

RE: struct out {struct in{ char c;int d;}s1,*p1;...

hi frns
the above one ans is c
because a1 can hold only the value of s1 but not its address value........
abd more over p1 cant be hold by a1 so the a1 cant become pointer to p1

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