dey

• Jul 16th, 2005

 

ans:b

chayanika bhatnagar

• Sep 25th, 2005

 

i think the answer is : b)between 130 and 140 miles

suman

• Sep 26th, 2005

 

Between 120 and 140 miles

santi

• Dec 3rd, 2005

 

since max time is 8hrs d=40*4=120

gud_guy2006

 Profile Answers by gud_guy2006 

• Mar 7th, 2006

 

Anyone please explain how is thie ans to be derived?

hardeep singh

• Mar 17th, 2006

 

solution--- t1= time for forword journey. t2 =time 4 return journey. t=t1 + t2 =8hrs; x= destination; t1 + t2 = x / 40 + x / 30 = 8; x( 7/120 ) = 8; x= 8*120/ 7 = 137 milesie answer is(b) if u hav any question , mail me at hardeep.cusat@gmail.com 4 getting answer.

Bhavna

• Mar 17th, 2006

 

it has to be (a)as the max distance comes out to be 137.14

shivani

• Oct 4th, 2006

 

let t1 be the time taken for forward journey and t2 be for returning journey.

distance= speed*time

so d1=40t1

d2=30t2

since distance is same d1=d2

so 40t1=30t2 and t1+ t2=8 solving thease two equation we will be having ans between 120 and 140 miles

beno

• Jun 8th, 2007

 

This person can travel 8 hours a day. He can travel up to 240m. So he can return on Sunday also.

arun_navgo

 Profile Answers by arun_navgo 

• May 17th, 2008

 

the max distance is 137... he cannot choose a distance of 138 or 139 miles..
so to the most positive side,the ans is 120miles

gaurisweet2

 Profile Answers by gaurisweet2 

• Aug 19th, 2008

 

The actual answer is 120 miles


total distance is 8 hrs

lets say time for forward t1 and back to home t2

t1+ t2 = 8 eqn 1

distance= time * speed

d1= 40t1
d2= 30t2

d1= d2

40t1= 30 t2

40t1-30t2= 0-----------eqn 2

solving eqn 1 and 2

t1= 2 hrs
t2 = 6 hrs

since its journey further from home


its 30 miles hour

therefore 30*6= 180 miles

since the distance is same

d1= 80 miles

therefore 180-80= 100

the answer is 120 or less

gaurisweet2

 Profile Answers by gaurisweet2 

• Aug 19th, 2008

 

d1= d2

distance = speed* time

40* t1= 30* t2

40t1-30t2=0
t1+t2= 8

40t1-30t2=0
30t1+30t2= 240


t1= 240/70
t1= 3.42857

t2= 8- 3.42857= 4.57143

d1= 3.42857 * 30

102.8571 miles

d2= 4.57143*40 = 182.85

the further distance is 182-102= 82 miles

so the answer is 120 miles or less

tiru5796

 Profile Answers by tiru5796 

• Jun 9th, 2009

 

If he travels with a speed of  40m/h in 8 hours=320miles he can travel

If he travels with a speed of  30m/h in 8hours=240miles he can travel
 
let us take he travels half time(4hours)in forward =160miles he travel with 40m/h

In return stage he travel(4 hours)=120miles/h with 30m/h speed

In return journey he take more than half time. so the distance is lies between 120 to 140 miles.
 

jpprakash

 Profile Answers by jpprakash 

• Nov 5th, 2009

 

Average speed =2ab/(a+b)
a=40mph
b=30mph
simplifying we get 240/7

speed=distance/time


we have average speed=240/7

time=8/2 =4.  because 8hrs=(going+coming)

equating for distance we get d=s*t       d=240/7*4= 137.14
Therefor he cannot choose a distance which is greater than 137.14, so the answer is
a) 120 miles

rajendraprasad349

 Profile Answers by rajendraprasad349 

• Aug 27th, 2010

 

Let distance = 'd'
Let us assume forward journey time is 't1'
Return journey time is 't2'
Given t1+t2=8
But time = distance / velocity
t1 = d/40
t2 = d/30
Therefore t1+t2 = d/40 + d/30 = 8
d=137.142

RAJU KUMAR

• Oct 23rd, 2011

 

b)
let he can select a picnic spot =x m
.
. . x/40+x/30=8
x=137.1 m
so ans is b.