 Related Questions A soft. Eng just returned from US has eaten too much fat and put a lot of weight. So he wanted to less his weight. Every Sunday he starts walking at 3pm with 4 km/hr on level ground then up to at 3 km/hr. he comes back down hill with 6 km/hr and similar speed as previous on level ground till he reaches his destiny at 9 pm . Find his total distance. 24 km A man had covered 2/3 of distance by cycling and remaining covered on feet. For this he took twice the time to the cycling. Find how much speed is greater for cycling than on feet. A person from washington came to india.One evening at 6.00 p m he started walking at the speed of 40 km/hr andclimbed the slope at speed of 30 km/hr.From there he walked back to the source at the same speed at 9.00 p m.what is the distance he covered in one way. 12 kms Two trains each 1/6 mile in length run in opposite dirctions to each other with equal speed of 60 miles/hour. What is the time taken to completelycross over the two trains. Speed at which two trains travel towards each other = 60+60 = 120 miles/hour.Total length to be covered = (1/6)+(1/6) = 2/6 mile.Time to taken to cover 2/6 mile at speed of 120 miles/hour is.....(2/6)/120 A man wearing a hat stands on a bridge across a river. At an instant his hat falls into the river and starts flowing along with the stream at the same speed of the stream.At the same instant the man jumps into the river and starts swimming in the directionopposite to the stream, like that he swims for 10 minute , then he turns back and starts swimming in the direction of the stream to retrieve the hat. He retrieves the hatunder another bridge which is 1000 yards away down the stream from the first Let the swimming speed of man be = a yds/min.speed of stream = b yds/min.Then the man swims at (a-b) yds/min. against the stream.and (a+b) yds/min in direction with the stream.Lets assume the man covered A train travels at a particular speed for a duration of one hour, after which one of its engine malfunctions reducing its speed to 3/5th of the actual speed before theoccurrence of fault in engine. It travels at this speed for 2 hours to reach at itsdestination. If the fault had occurred 50 miles later on, the train would have reachedits destination 45 minutes early. Find the distance traveled by the train. Let the actual speed of train be X miles/hour. after fault its speed will be reduced to 3X/5 miles/hour. If we could find the speed of the train, we will get the solution!!!by seeing one can find that Old Man WrinkleMan Wrinkle spent one-fourth of his life as a boy, one-eighth as a youth, and one-half as an active man. If Man Wrinkle spent 8 years as an old man, then how many years did he spend as an active man? (1/4)y+(1/8)y+(1/2)y =p; where y =total life time.y-p=8.since p=(14/16)ywe've y=64active age=32 Vacation timeIt was vacation time, and so I decided to visit my cousin's home. What a grand time we had! In the mornings, we both would go for a jog. The evenings were spent on the tennis court. Tiring as these activities were, we could manage only one per day, i.e., either we went for a jog or played tennis each day. There were days when we felt lazy and stayed home all day long. Now, there were 12 mornings when we did nothing, 18 evenings when we stayed at home, and a total of 14 days Use sets and venn diagram to solve such questions.a,b ,aub,anb etc.12=tennis+leave18=jog +leaveso jog-tennis=6again jog+tennis=14.so solve and get jog=10,leave=8,tennis=4.so tot=22 Albert and Fernandes have two leg swimming race. Both start from opposite and of the pool. On the first leg, the boys pass each other at 18 mt from the deep end of the pool. During the II leg they pass at 10 mt from the shallow end of the pool. Both go at const speed. But one of them is faster. Each boy rests for 4 sec to see at the end of the I leg. What is the length of the pool. Read Answers (2) | Asked by : sharad vasisht Two people X & Y walk on the wall of a go down in opposite direction. They meet at a point on one side and then go ahead. X after walking for some time, walks in opposite direction for 15 mtrs. Then again he turns back and walks in the original direction. What distance did Y walk before they met again, if X walks 11 mtrs by the time Y walks 8 mtrs. View Question | Asked by : sharad vasisht
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