A cow was standing on a bridge, 5feet away from the middle of the bridge. suddenly a lightning express with 90 miles/hr was coming towards the bridge from nearest end of the cow.seeeing this the cow ran towards the express and managed to escape when the train is one feet away from the bridge. if it would have ran to opposite direction(ie away from train) it would have been hit the train one ft away from the end of the bridge. Calculate the length of bridge. speed of the cow.

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rajmishra4u
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Jul 27th, 2006
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shiv kumar chaudhary

Aug 1st, 2006

solution as:
iif we take distance of train from bridge = x+1
cow speed v, and bridge length 2d then applying relative distance we got eqn.
1 = (90-v)*((d-5)/v); and in second case
0 = (90+v)*((d+4)/v). 2 eqn 2 ver. solving..
bridge length 2d = 3 + (361)^1/2;
and v = 9(2d - 1).