praveen

• Aug 2nd, 2006

 

50

hari rama chandran

• Aug 22nd, 2006

 

25*70=175050*60=3000--------------------25 1250variable cost = 1250/25=50fixed cost=1750-25*50=500therefore for 100100*50+500=5500per board=5500/100=55

mandar dindorkar

• Sep 19th, 2006

 

let total cost be c= a + nk

where a = fixed cost and

k = variable cost and n = number of boarders

total cost when 25 boarders c = 25*70 = 1750 i.e. 1750 = a + 25k

total cost when 50 boarders c = 50*60 = 3000 i.e. 3000 = a + 50k

solving above 2 eqns, 3000-1750 = 25k i.e. 1250 = 25k i.e. k = 50

therefore, substituting this value of k in either of above 2 eqns we get

a = 500 (a = 3000-50*50 = 500 or a = 1750 - 25*50 = 500)

so total cost when 100 boarders = c = a + 100k = 500 + 100*50 = 5500

so cost per head = 5500/100 = 55

arina

 Profile Answers by arina 

• Jan 1st, 2010

 

Let fixed cost=a, variable cost=k
We can write a+25k=70*25=1750
a+50k=3000
We get k=50
then a=3000-(50*25)=500
Charge per head= (500+100*50)/100  = 55

KABILAVARMEN

• Aug 31st, 2016

 

for 25 members = 25*70=1750
for 50 members = 50*60=3000
therefore 3000-1750=1250
so, 1750-1250=500 this 5oo is common.
therefore 1250 for every 25 members
therfore to check for 25 members we know Rs.1750 = 1*1250+500=1750(one 25s)
for 50 members we know Rs.3000 =2*1250+500=3000( two 25s)
therefore for 100 (four 25s)=4*1250+500=5500 therefore 5500/100=55