3 men finish painting a wall in 8 days. Four boys do the same job in 7 days. In how many days will 2 men and 2 boys working together paint two such walls of the same size? a) 6 6/13 days b) 3 3/13 days c) 9 2/5 days d) 12 12/13 days

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Questions by nurankl84   answers by nurankl84

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keerthi

  • Jul 14th, 2006
 

The ans for this q is 6 6/13

mandar dindorkar

  • Sep 19th, 2006
 

3 men -> 8 days

as men decrease => days increase

=> 1 man ->24 days =>1 man's 1 day work = 1/24

4 boys -> 7 days

=> 1 boy ->28 days => 1 boy's 1 day work = 1/28

so 2 men + 2 boys 1 day work = 2/24 + 2/28 = 1/12+ 1/14 = 13/84

so 2men + 2boys finish 13/84 of work in 1 day

so days  to finish total work = 84/13 i.e 6 6/13

abbs

  • Dec 27th, 2006
 

The answer is D. We have been asked to calculate days required to paint TWO such walls hence 2*84/13 i.e. 12 12/13 days is the answer.

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Akshaya

  • Sep 17th, 2007
 

The answer is 3 3/13 .
b coz...
He asks 2men and 2 boys working together to paint 2 walls not for a one wall.

2 men + 2 boys takes 6 6/13 days to paint for a one wall

For 2 walls it will be 3 3/13.

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subhrojitn

  • Feb 10th, 2008
 

i man can paint 1/24 th part of the wall
i boy paints 1/28 th part

 .
. . 2 boys and 2 men paints 1/12+1/14 th part;13/84 th part in one day
 .
. . to complete one wall they take 84/13 days

 .
. . two walls takes 2*84/13 days
         12
or 12 ---    days
         13

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3 men 8 days
each day 3 men will do 1/8 th work
each day 1 man will do 1/24th work
4 boys 7 days
each day 4 boys will do 1/7 th work
each day 1 boy will do 1/28th work

so 2 men+2 boys for 1 wall for 1 day =2/24+2/28=13/84
total no. of days for 1 wall =84/13=6 6/13
 total no. of days for 2 walls=12 6/13

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ans is 6 6/13
to calculate it
1. 3 men in=1/8 days
so 1 men in =1/24
similarly 1 boy in=1/28
so now calulate for 2 men n 2 boy together=1/12+1/14
which is for 1 wall
now for 2 wall it will b=(1/12+1/14)/2

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