CTS - A,B,C r positive int.Out of them 2 r odd. Then 52a + ( b-5)3 (c-3)2 =

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A,B,C r positive int.Out of them 2 r odd. Then 52a + ( b-5)3 (c-3)2 =

Total Answers and Comments: 7

Last Update: January 30, 2008 Asked by: danie

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July 05, 2006 02:40:23

#1

Natarajan

RE: A,B,C r positive int.Out of them 2 r odd. Then 52a...

Ans is 52.

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July 17, 2006 01:50:28

#2

shravan

RE: A,B,C r positive int.Out of them 2 r odd. Then 52a...

if we take a,b,c as 7,8,9 respectively, then answer will be something. if we take other values then its different, so answer cannot be determined.

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July 25, 2006 02:27:19

#3

CHANDRA SEKHAR REDDY.MURE

RE: A,B,C r positive int.Out of them 2 r odd. Then 52a...

then i take a,b,c values are 2,,5,3then apply these values result is 104

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July 30, 2006 12:50:40

#4

mpk

RE: A,B,C r positive int.Out of them 2 r odd. Then 52a...

even but cant be determine about the values.OK.

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August 09, 2006 00:55:47

#5

VAIDHYA

to question

The answer is EVEN . There is no question of value .......... CHECK IT OUT

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January 29, 2007 07:09:14

#6

ankitbandyopadhyay

Member Since: January 2007 Contribution: 5

RE: A,B,C r positive int.Out of them 2 r odd. Then 52a...

It cant be said odd or evencase1)Say b is evensay 88-5=3*5 is always oddsince one is even other two is oddOther is a multiple of 2 which is always eveneven+odd+even=oddcase2)b is oddb-5 is even(b-5)*5 is evenOther two is a multiple of two always eveneven+even+even=even

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January 30, 2008 09:22:32

#7

Member Since: December 2007 Contribution: 2

RE: A,B,C r positive int.Out of them 2 r odd. Then 52a + ( b-5)3 (c-3)2 =

i think the answer will always come out to be even.

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