RE: a man walks 3km east then 5km north then 8km east ...
from a starting point he/she travels 3km east and 5km north. so 6km(root(5^2+3^2)) far from northeast. plus 8km is 14 km notheast from the starting point.
RE: a man walks 3km east then 5km north then 8km east ...
if u draw a rectangle of length of total(3+8) km and breadth 5km and draw a diagonal from the starting to ending point by Pythagaros Theorem square(hyp) square(the both sides)